In many applications very large integers numbers are required. Some of these applications are using keys for secure transmission of data, encryption, etc. In th...
Problem Description A DFS(digital factorial sum) number is found by summing the factorial of every digit of a positive integer.
通常，正整数 n 的阶乘是所有小于或等于 n 的正整数的乘积。例如，factorial(10) = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1。
题解：一个数的阶乘结果的末尾的0，根据分解质因数，只能是25得到的，所以把这个数的阶乘分解质因数，看有多少个25，2显然是比5多的，所以数一数有多少个5就可以了。...
object EmbedDemo { def add3(x:Int,y:Int,z:Int)={ def add2(x:Int,y:Int)={ x+y } add2(add2(x,y),z) } def main(args: Array[String]): Unit = { p...
思路： 考虑125!有多少个0？实际上是求1 * 2 * 3 * … * 125 有多少个5。
Write an algorithm which computes the number of trailing zeros in n factorial.
