代码语言:javascript复制
// Time complexity O(n*n)
class Solution {
public:
string longestPalindrome(string s) {
int startIdx = 0, left = 0, right = 0, len = 0;
for (int i = 0; i < s.size() - 1; i) {
if (s[i] == s[i 1]) {
left = i;
right = i 1;
searchPalindrome(s, left, right, startIdx, len);
}
left = right = i;
searchPalindrome(s, left, right, startIdx, len);
}
if (len == 0) len = s.size();
return s.substr(startIdx, len);
}
void searchPalindrome(string s, int left, int right, int &startIdx, int &len) {
int step = 1;
while ((left - step) >= 0 && (right step) < s.size()) {
if (s[left - step] != s[right step]) break;
step;
}
int wide = right - left 2 * step - 1;
if (len < wide) {
len = wide;
startIdx = left - step 1;
}
}
};