python+playwright 学习-77 playwright 发送接口请求APIRequestContext

前言

每个Playwright浏览器上下文都有与其关联的APIRequestContext实例，该实例与浏览器上下文共享cookie存储，可以通过browser_context.request或page.request访问。也可以通过调用api_request.new_context（）手动创建一个新的APIRequest上下文实例。

通过浏览器发请求

可以通过browser_context.request或page.request发送接口请求，该实例与浏览器上下文共享cookie存储。

page.request() 发送请求

也可以通过page.request() 发送接口请求

代码语言：javascript复制

from playwright.sync_api import sync_playwright, expect

with sync_playwright() as p:
    browser = p.chromium.launch(headless=False)
    context = browser.new_context()
    page = context.new_page()

    page.goto('https://www.cnblogs.com/yoyoketang/')


    # 发post请求
    resp = page.request.post(
        url="http://www.example.com/",
        data={"user": "test", "email": "123@qq.com"}
    )
    print(resp.status)
    print(resp.headers)
    print(resp.body())

APIRequestContext

不打开浏览器的情况下，直接发接口请求也是可以的

代码语言：javascript复制

from playwright.sync_api import sync_playwright

with sync_playwright() as p:
    context = p.request.new_context()
    response = context.get("https://example.com/user/repos")
    assert response.ok
    assert response.status == 200
    assert response.headers["content-type"] == "application/json; charset=utf-8"
    assert response.json()["name"] == "foobar"
    assert response.body() == '{"status": "ok"}'

python 存储 playwright 接口 浏览器

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