python 选择上传文件的实现

代码语言：javascript复制

import tkinter as tk
from tkinter import filedialog

def upload_file():
    selectFile = tk.filedialog.askopenfilename()  # askopenfilename 1次上传1个；askopenfilenames1次上传多个
    entry1.insert(0, selectFile)

root = tk.Tk()

frm = tk.Frame(root)
frm.grid(padx='20', pady='30')
btn = tk.Button(frm, text='上传文件', command=upload_file)
btn.grid(row=0, column=0, ipadx='3', ipady='3', padx='10', pady='20')
entry1 = tk.Entry(frm, width='40')
entry1.grid(row=0, column=1)

root.mainloop()

python grid import root upload

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