这题目用java是会超时的，我提供java代码，自己对照去写c ，用c 最后一个测试点100ms左右，估计用java需要500-600ms，会超时，一般200ms的用java能过的可能性就比较小了，倒数第二个测试点如果出现段错误就是你的数组越界了，没有考虑全部错误的情况，输出0，最后一个测试点数据有点大，如果是错误，就是放进容器时的判断条件有错。
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
import java.util.Scanner;
class Person {
public int year, month, day;
public String name;
public Person(int year, int month, int day, String name) {
this.year = year;
this.month = month;
this.day = day;
this.name = name;
}
}
public class Main {
public static int year, month, day;
public static void main(String[] args) {
List<Person> list = new ArrayList<Person>();
Scanner cin = new Scanner(System.in);
int n = cin.nextInt(), count = 0;
for (int i = 0; i < n; i) {
String name = cin.next();
String[] c = cin.next().split("/");
year = Integer.parseInt(c[0]);
month = Integer.parseInt(c[1]);
day = Integer.parseInt(c[2]);
if (isCheck()) {
list.add(new Person(year, month, day, name));
count;
}
}
if (count > 0) {
Collections.sort(list, new Comparator<Person>() {
@Override
public int compare(Person o1, Person o2) {
if (o1.year != o2.year) {
return o1.year - o2.year;
} else if (o1.month != o2.month) {
return o1.month - o2.month;
} else {
return o1.day - o2.day;
}
}
});
System.out.println(count " " list.get(0).name " " list.get(count-1).name);
}
else {
System.out.println(0);
}
}
public static boolean isCheck() {
if (year > 2014 || year < 1814)
return false;
else if (year == 2014) {
if (month > 9)
return false;
else if (month == 9) {
if (day > 6)
return false;
}
} else if (year == 1814) {
if (month < 9)
return false;
else if (month == 9) {
if (day < 6)
return false;
}
}
return true;
}
}
