一、题目
1. 计算下列极限
- (1)
- (2)
- (3)
- (4)
2. 计算下列导数
- (1) 求
,
- (2) 求
,
- (3) 求
,
- (4)
3. 计算下列定积分
- (1)
- (2)
- (3)
4. 计算下列级数的和
- (1)
- (2)
- (3)
二、解答
题一,计算下列极限
①
代码语言:javascript复制>> syms x
>> y = ((1 x)^(1/2)-(1-x)^(1/2))/((1 x)^(1/3)-(1-x)^(1/3))
y =
((x 1)^(1/2) - (1 - x)^(1/2))/((x 1)^(1/3) - (1 - x)^(1/3))
>> limit(y,x,0)
ans =
3/2
②
代码语言:javascript复制>> syms x
>> y = ((3*x 2)/(3*x-1))^(2*x-1)
y =
((3*x 2)/(3*x - 1))^(2*x - 1)
>> limit(y,x,0)
ans =
-1/2
③
代码语言:javascript复制>> syms x
>> y = ((1/x^2)-1/(sin(x)^2))
y =
1/x^2 - 1/sin(x)^2
>> limit(y,x,0)
ans =
-1/3
④
代码语言:javascript复制>> syms x
>> y = (pi/2 - atan(x))^(1/(log(x)))
y =
(pi/2 - atan(x))^(1/log(x))
>> limit(y,x,0)
ans =
1
题二,计算下列导数
①
代码语言:javascript复制>> y = (x^(1/2) 1)*atan(x)
y =
atan(x)*(x^(1/2) 1)
>> diff(y,x)
ans =
atan(x)/(2*x^(1/2)) (x^(1/2) 1)/(x^2 1)
②
代码语言:javascript复制>> y = (1 x^2)/(sin(x) cos(x))
y =
(x^2 1)/(cos(x) sin(x))
>> y1 = diff(y,x)
y1 =
(2*x)/(cos(x) sin(x)) - ((x^2 1)*(cos(x) - sin(x)))/(cos(x) sin(x))^2
>> y2 = diff(y1,x)
y2 =
(x^2 1)/(cos(x) sin(x)) 2/(cos(x) sin(x)) (2*(x^2 1)*(cos(x) - sin(x))^2)/(cos(x) sin(x))^3 - (4*x*(cos(x) - sin(x)))/(cos(x) sin(x))^2
③
代码语言:javascript复制>> y = (x (x (x)^(1/2))^(1/2))^(1/2)
y =
(x (x x^(1/2))^(1/2))^(1/2)
>> diff(y,x)
ans =
((1/(2*x^(1/2)) 1)/(2*(x x^(1/2))^(1/2)) 1)/(2*(x (x x^(1/2))^(1/2))^(1/2))
④
代码语言:javascript复制>> syms x y t a
>> x = a*(cos(t) t*sin(t))
x =
a*(cos(t) t*sin(t))
>> y = a*(sin(t)-t*cos(t))
y =
a*(sin(t) - t*cos(t))
>> dx = diff(x,t)
dx =
a*t*cos(t)
>> dy = diff(y,t)
dy =
a*t*sin(t)
>> dy/dx
ans =
sin(t)/cos(t)
题三,计算下列定积分
①
代码语言:javascript复制>> syms x y
>> y = cos(x)/(1 (sin(x))^2)
y =
cos(x)/(sin(x)^2 1)
>> int(y,x,0,pi/2)
ans =
pi/4
②
代码语言:javascript复制>> syms x y a
>> y = (x^2)*((a-x)/(a x))^(1/2)
y =
x^2*((a - x)/(a x))^(1/2)
>> int(0,a)
ans =
0
>> int(y,x,0,a)
ans =
(a^3*(3*pi - 8))/12
③
代码语言:javascript复制>> syms x y a
>> y = 1/((x^2-x 1)^(3/2))
y =
1/(x^2 - x 1)^(3/2)
>> int(y,x,0,1)
ans =
4/3
题四,计算下列级数的和
①
代码语言:javascript复制>> syms x y n
>> y = 1/(n^2)
y =
1/n^2
>> symsum(y,n,1,Inf)
ans =
pi^2/6
②
代码语言:javascript复制>> y = (-1)^(n-1)/n
y =
(-1)^(n - 1)/n
>> symsum(y,n,1,Inf)
ans =
log(2)
③
代码语言:javascript复制>> y = (x^(2*n-1))/(2*n-1)
y =
x^(2*n - 1)/(2*n - 1)
>> symsum(y,n,1,Inf)
ans =
piecewise(abs(x) < 1, atanh(x))