C语言实现推箱子小游戏 包括黑窗和图形界面 参考视频 https://www.bilibili.com/video/BV1By4y1a79o?t=4428 BUG:当人进入到目的地的时候会无法移动。
代码语言：javascript复制#include<stdio.h>
#include<stdlib.h>
//这个库函数不是C 语言标准的，在VS上可以直接用，在Linux上就不行。
#include<conio.h>
//使用布尔类型
#include<stdbool.h>
//使用图形界面-图形界面头文件（需要安装）
#include<graphics.h>
//推箱子
//知识点：数组 、函数、
//开发环境 vs2019
//准备地图数据 用二维数组来存储
//表示——空地 0 墙 1 目的地 2 箱子 3 玩家 4
//这两个是动态变化的 箱子 目的地 5 玩家 目的地 6
//难点在于判断移动导致的变化
#define SPACE 0
#define WALL 1
#define DEST 2
#define BOX 3
#define PLAYER 4
#define ROW 10
#define COL 10
//当前所在关卡
int level = 0;
//变成3纬数组 可以存多个地图
int map[3][ROW][COL] =
{
//设计地图样式
//map1
{
{0,0,0,0,0,0,0,0,0,0},
{0,0,0,1,1,1,0,0,0,0},
{0,0,0,1,2,1,0,0,0,0},
{0,0,0,1,3,1,1,1,1,0},
{0,1,1,1,0,3,0,2,1,0},
{0,1,2,3,4,0,1,1,1,0},
{0,1,1,1,1,3,1,0,0,0},
{0,0,0,0,1,2,1,0,0,0},
{0,0,0,0,1,1,1,0,0,0},
{0,0,0,0,0,0,0,0,0,0}
},
//map2
{
{0,0,0,0,0,0,0,0,0,0},
{0,0,1,1,0,0,1,1,0,0},
{0,1,0,2,1,1,2,0,1,0},
{1,0,0,0,0,0,0,0,0,1},
{1,0,0,3,0,3,0,0,0,1},
{1,0,0,0,4,0,0,0,0,1},
{0,1,0,3,0,3,0,0,1,0},
{0,0,1,2,0,0,2,1,0,0},
{0,0,0,1,0,0,1,0,0,0},
{0,0,0,0,1,1,0,0,0,0}
},
//map3
{
{0,0,0,0,0,0,0,0,0,0},
{0,1,1,1,1,1,1,1,1,0},
{0,1,2,0,0,0,0,2,1,0},
{0,1,0,0,0,0,0,0,1,0},
{0,1,0,3,0,3,0,0,1,0},
{0,1,0,0,4,0,0,0,1,0},
{0,1,0,3,0,3,0,0,1,0},
{0,1,2,0,0,0,0,2,1,0},
{0,1,1,1,1,1,1,1,1,0},
{0,0,0,0,0,0,0,0,0,0}
}
};
//定义一个图片的数组int image
IMAGE img[6];
//加载图片
void loadImg()
{
for (int i = 0; i < 6; i )
{
char temFileName[50] = { 0 };
sprintf_s(temFileName,"./images/%d.bmp", i);
loadimage(img i, temFileName, 63, 63); //项目属性-高级-字符集-使用多字符字符集
}
}
void DrawMap()
{
for (int i = 0; i < 10; i )
{
for (int k = 0; k < 10; k )
{
switch (map[level][i][k])
{
case SPACE:
putimage(k * 63, i * 63, img 0);
break;
case WALL:
putimage(k * 63, i * 63, img 1);
break;
case DEST:
putimage(k * 63, i * 63, img 2);
break;
case BOX:
putimage(k * 63, i * 63, img 3);
break;
case PLAYER:
putimage(k * 63, i * 63, img 4);
break;
case BOX DEST:
putimage(k * 63, i * 63, img 5);
break;
case PLAYER DEST:
putimage(k * 63, i * 63, img 5);
break;
default:
printf("%d ", map[level][i][k]);
break;
}
}
printf("n");
}
}
void show()
{
for (int i = 0; i < 10; i )
{
for (int k = 0; k < 10; k )
{
switch (map[level][i][k])
{
case SPACE:
printf(" ");
break;
case WALL:
printf("▓");
break;
case DEST:
printf("☆");
break;
case BOX:
printf("★");
break;
case PLAYER:
printf("♂");
break;
case BOX DEST:
printf("◇");
break;
case PLAYER DEST:
printf("♀");
break;
default:
printf("%d ", map[level][i][k]);
break;
}
}
printf("n");
}
}
void pushBox()
{
//找到玩家所在的下标
//地图里面哪些数据有可能是玩家
//PLAYER PLAYER DEST
int i = 0;
int k = 0;
for ( i = 0; i < 10; i )
{
for ( k = 0; k<10; k )
{
if (map[level][i][k] == PLAYER)
{
goto end;
break;
}
}
}
end:;//goto到这里
//获取键盘按键 - _getch()-一触即发不需要按回车 getchar()-输入之后需要按回车
char key = _getch();
//printf("%d %cn", key, key);
switch (key)
{
case 'w':
case 'W':
case 72://向上移动
//什么情况下 玩家才能移动 才能推箱子？
//玩家的前面是空地(目的地)、玩家的前面是箱子（箱子的前面是什么） 可以动
//如果玩家的前面是空地
if (map[level][i- 1][k] == SPACE || map[level][i - 1][k] == DEST)
{
map[level][i - 1][k] = PLAYER;
map[level][i][k] -= PLAYER;
}
else if(map[level][i-1][k] == BOX)//玩家的前面是箱子
{
if (map[level][i - 2][k] == SPACE || map[level][i - 2][k] == DEST)//箱子的前面是空地或者是目的地
{
map[level][i - 2][k] = BOX;
map[level][i - 1][k] = (PLAYER - BOX);
map[level][i][k] -= PLAYER;
}
}
break;
case 's':
case 'S':
case 80://向下移动
if (map[level][i 1][k] == SPACE || map[level][i 1][k] == DEST)
{
map[level][i 1][k] = PLAYER;
map[level][i][k] -= PLAYER;
}
else if (map[level][i 1][k] == BOX)//玩家的前面是箱子
{
if (map[level][i 2][k] == SPACE || map[level][i 2][k] == DEST)//箱子的前面是空地或者是目的地
{
map[level][i 2][k] = BOX;
map[level][i 1][k] = (PLAYER - BOX);
map[level][i][k] -= PLAYER;
}
}
break;
case 'a':
case 'A':
case 75://向左移动
if (map[level][i][k - 1] == SPACE || map[level][i][k - 1] == DEST)
{
map[level][i][k - 1] = PLAYER;
map[level][i][k] -= PLAYER;
}
else if (map[level][i][k - 1] == BOX)//玩家的前面是箱子
{
if (map[level][i][k - 2] == SPACE || map[level][i][k - 2] == DEST)//箱子的前面是空地或者是目的地
{
map[level][i][k - 2] = BOX;
map[level][i][k - 1] = (PLAYER - BOX);
map[level][i][k] -= PLAYER;
}
}
break;
case 'd':
case 'D':
case 77://向右移动
if (map[level][i][k 1] == SPACE || map[level][i][k 1] == DEST)
{
map[level][i][k 1] = PLAYER;
map[level][i][k] -= PLAYER;
}
else if (map[level][i][k 1] == BOX)//玩家的前面是箱子
{
if (map[level][i][k 2] == SPACE || map[level][i][k 2] == DEST)//箱子的前面是空地或者是目的地
{
map[level][i][k 2] = BOX;
map[level][i][k 1] = (PLAYER - BOX);
map[level][i][k] -= PLAYER;
}
}
break;
default:
break;
}
}
//什么情况下才过关呢，当前关卡没有箱子了 就通关了
bool Judge()
{
for (int i = 0; i < ROW; i )
{
for (int k = 0; k < COL; k )
{
if(map[level][i][k] == BOX)
{
return false;
}
}
}
return true;
}
int main(void)
{
//设置黑窗口的大小
system("mode con cols=30 lines=20");//设置cols和lines数值的时候不能有空格，否则会报错。
//创建图形界面窗口
//参数 窗口的宽度 高度 SHOWCONSOLE表示同时显示控制台和控制台
initgraph(ROW*63,COL*63,SHOWCONSOLE);
//Easyx只能用于C ,所以源文件后缀改为.cpp
loadImg();
while (1)
{
system("cls");
show();
DrawMap();
//判断是否过关
if (Judge())
{
//切换关卡
level ;//最大只有三关，超过了就数组越界了
if (level > 2)
{
exit(0);
}
printf("按任意键进入下一关......n");
}
pushBox();
}
//getchar();——防止闪退的，加了while 1就不需要了
return 0;
}
