题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3309
一道典型的Hash题
题目很好理解。这里不复述
由于输入语句最大数量200000,不用Hash铁定TLE。然后数据量不超过10000,所以必然有很多search和reply的操作。
对于这个稍微做下优化就OK了
贴代码:
代码语言:javascript复制#include <iostream>
#include <cstring>
#include <vector>
using namespace std;
const long hashsize = 51071; //Hash表大小
unsigned long ELFHash(char* strIn)
{
unsigned long hashInt = 0 ;
unsigned long x = 0 ;
long i;
for (i = 0; i <= strlen(strIn) - 1; i )
{
hashInt = (hashInt << 4) strIn[i];
if ((x = hashInt & 0xF0000000L) != 0)
{
hashInt ^= ( x >> 24 ) ;
hashInt &= ~x ;
}
}
return (hashInt & 0x7FFFFFFF) % hashsize;
}
template<typename _T>
class _My_Hash_ToInt_Data
{
public:
_My_Hash_ToInt_Data()
{
times = 0;
next = -1;
}
_T data;
long times;
long next;
};
template<long _SZ,class _T, unsigned long pFun(_T& _Off)>
class _My_Hash_ToInt
{
public:
_My_Hash_ToInt()
{
memset(hash, -1, sizeof(hash));
length = 0;
};
~_My_Hash_ToInt(){};
long find(_T _Off)
{
long pos = hash[pFun(_Off)];
while(pos >= 0)
{
if(data[pos].data == _Off)
return pos;
else
pos = data[pos].next;
}
return -1;
}
long insert(_T _Off)
{
long oldPos = pFun(_Off);
long pos = hash[oldPos];
while(pos >= 0)
{
if(data[pos].data == _Off)
{
data[pos].times ;
return pos;
}
else
pos = data[pos].next;
}
data[length].data = _Off;
data[length].times = 1;
data[length].next = hash[oldPos];
hash[oldPos] = length ;
return length ;
}
void clear()
{
length = 0;
memset(hash, -1, sizeof(hash));
memset(data, -1, sizeof(data));
}
//Member
long length;
_My_Hash_ToInt_Data<_T> data[_SZ];
long hash[hashsize];
};
class node
{
public:
char str[60];
bool operator == (node &strin)
{
return !strcmp(str, strin.str);
}
node& operator = (node &strin)
{
strcpy(str, strin.str);
return (*this);
}
};
unsigned long ELFHashEx(node &strIn)
{
return ELFHash(strIn.str);
}
_My_Hash_ToInt<10005, node, ELFHashEx>hash;
long usedR[10005] = {0};
vector<long>list;
char cmd[10];
int main()
{
long n,round = 0, i;
long hashlen = 0;
node str;
while(scanf("%ld", &n) != EOF)
{
round ;
hash.clear();
list.clear();
while(n --)
{
scanf("%s", cmd);
if(!strcmp("new", cmd))
{
scanf("%s", str.str);
hashlen = hash.insert(str);
usedR[hashlen] = round;
list.push_back(hashlen);
hashlen ;
}
else if(!strcmp("reply", cmd))
{
scanf("%s", str.str);
long pos = hash.find(str);
usedR[pos] = round;
list.push_back(pos);
}
else if(!strcmp("tag", cmd))
{
scanf("%s", str.str);
long pos = hash.find(str);
usedR[pos] = 0;
}
else if(!strcmp("search", cmd))
{
long outN = 100;
for(i = list.size() - 1; i >= 0 && outN; i --)
{
if(usedR[list[i]] && usedR[list[i]] <= round)
{
printf("%sn", hash.data[ list[i] ].data.str );
usedR[list[i]] = round 1;
outN --;
}
}
printf("###n");
round ;
}
}
putchar('n');
}
return 0;
}
使用STL又过了一遍。内存消耗减少了近300kb,时间大概是原来的3倍。370Ms
代码语言:javascript复制#include <iostream>
#include <cstring>
#include <vector>
#include <string>
#include <map>
using namespace std;
map<string, long>hash;
long usedR[10005] = {0};
vector<long>list;
char cmd[10];
string strO[10005];
int main()
{
long n,round = 0, i;
long hashlen = 0;
string str;
while(scanf("%ld", &n) != EOF)
{
round ;
hashlen = 0;
hash.clear();
list.clear();
while(n --)
{
scanf("%s", cmd);
if(!strcmp("new", cmd))
{
cin>> str;
hash[ str ] = hashlen;
usedR[hashlen] = round;
list.push_back(hashlen);
strO[hashlen] = str;
hashlen ;
}
else if(!strcmp("reply", cmd))
{
cin>> str;
long pos = hash[str];
usedR[pos] = round;
list.push_back(pos);
}
else if(!strcmp("tag", cmd))
{
cin>> str;
long pos = hash[str];
usedR[pos] = 0;
}
else if(!strcmp("search", cmd))
{
long outN = 100;
for(i = list.size() - 1; i >= 0 && outN; i --)
{
if(usedR[list[i]] && usedR[list[i]] <= round)
{
cout<< strO[ list[i] ]<< endl;
usedR[list[i]] = round 1;
outN --;
}
}
printf("###n");
round ;
}
}
putchar('n');
}
return 0;
}