Python 交错合并多个list列表的方法及示例代码
示例代码：
代码语言：javascript复制l1 = ["a","b","c","d"]
l2 = [1,2,3,4]
l3 = ["w","x","y","z"]
l4 = [5,6,7,8]实现效果：
代码语言：javascript复制l5 = ["a",1,"w",5,"b",2,"x",6,"c",3,"y",7,"d",4,"z",8]1、直接使用" "号合并列表
代码语言：javascript复制l5 = l1 l2 l3 l4 2、使用extend方法
代码语言：javascript复制l5 = l1.extend(l2,l3,l4,l5) 3、使用append方法
代码语言：javascript复制aList = [1,2,3]
bList = ['www', 'jb51.net']
aList.append(bList)
print(aList)
# 输出：
[1, 2, 3, ['www', 'jb51.net']]4、使用zip()实现
文档：zip()
代码语言：javascript复制l1 = ["a", "b", "c", "d"]
l2 = [1, 2, 3, 4]
l3 = ["w", "x", "y", "z"]
l4 = [5, 6, 7, 8]
l5 = [x for y in zip(l1, l2, l3, l4) for x in y]
print(l5)输出：
代码语言：javascript复制['a', 1, 'w', 5, 'b', 2, 'x', 6, 'c', 3, 'y', 7, 'd', 4, 'z', 8]5、使用itertools.chain() 和 zip()
相关文档：itertools.chain 和 zip:
代码语言：javascript复制from itertools import chain
l1 = ["a", "b", "c", "d"]
l2 = [1, 2, 3, 4]
l3 = ["w", "x", "y", "z"]
l4 = [5, 6, 7, 8]
print(list(chain(*zip(l1, l2, l3, l4))))或者
代码语言：javascript复制print(list(chain.from_iterable(zip(l1, l2, l3, l4))))6、使用itertools实现
文档：itertool recipes
代码语言：javascript复制from itertools import cycle, islice
l1 = ["a","b","c","d"]
l2 = [1,2,3,4]
l3 = ["w","x","y","z"]
l4 = [5,6,7,8]
lists = [l1, l2, l3, l4]
def roundrobin(*iterables):
"roundrobin('ABC', 'D', 'EF') --> A D E B F C"
# Recipe credited to George Sakkis
num_active = len(iterables)
nexts = cycle(iter(it).__next__ for it in iterables)
while num_active:
try:
for next in nexts:
yield next()
except StopIteration:
# Remove the iterator we just exhausted from the cycle.
num_active -= 1
nexts = cycle(islice(nexts, num_active))
print(*roundrobin(*lists)) 7、使用切片实现
代码语言：javascript复制l1 = ["a","b","c","d"]
l2 = [1,2,3,4]
l3 = ["w","x","y","z"]
l4 = [5,6,7,8]
lists = [l1, l2, l3, l4]
lst = [None for _ in range(sum(len(l) for l in lists))]
for i, l in enumerate(lists):
lst[i:len(lists)*len(l):len(lists)] = l
print(lst)
# demo1
aList = [1,2,3]
bList = ['www', 'jb51.net']
aList[len(aList):len(aList)] = bList
print(aList)
# 输出：
[1, 2, 3, 'www', 'jb51.net']
# demo2
aList = [1,2,3]
bList = ['www', 'jb51.net']
aList[1:1] = bList
print(aList)
# 输出为：
[1, 'www', 'jb51.net', 2, 3]8、使用pandas实现
代码语言：javascript复制import pandas as pd
l1 = ["a","b","c","d"]
l2 = [1,2,3,4]
l3 = ["w","x","y","z"]
l4 = [5,6,7,8]
df = pd.DataFrame([l1 ,l2, l3, l4])
result = list(df.values.flatten('A'))
print(result)9、使用numpy.dstack和flatten实现
代码语言：javascript复制import numpy as np
l1 = ["a","b","c","d"]
l2 = [1,2,3,4]
l3 = ["w","x","y","z"]
l4 = [5,6,7,8]
print(np.dstack((np.array(l1),np.array(l2),np.array(l3),np.array(l4))).flatten())或者
代码语言：javascript复制print(np.dstack((l1,l2,l3,l4)).flatten())10、使用zip() 和 np.concatenate()实现
代码语言：javascript复制import numpy as np
l1 = ["a","b","c","d"]
l2 = [1,2,3,4]
l3 = ["w","x","y","z"]
l4 = [5,6,7,8]
l5 = np.concatenate(list(zip(l1, l2, l3, l4)))
print(l5)11、使用zip()和reduce()
代码语言：javascript复制import functools, operator
l1 = ["a","b","c","d"]
l2 = [1,2,3,4]
l3 = ["w","x","y","z"]
l4 = [5,6,7,8]
print(functools.reduce(operator.add, zip(l1,l2,l3,l4)))
