stream-core实现枚举校验

2022-10-28 14:53:57 浏览数 (1)

同一个美丽而聪慧的人相处,能使人紧张的神经放松,感情变得柔和——巴尔扎尔

引入依赖:

代码语言:javascript复制
<!-- https://search.maven.org/artifact/io.github.vampireachao/stream-query -->
<dependency>
    <groupId>io.github.vampireachao</groupId>
    <artifactId>stream-core</artifactId>
    <version>1.1.12</version>
</dependency>

编写代码:

代码语言:javascript复制
@Test
void test() {

    class User {
        public GenderEnum getGender() {
            return null;
        }
    }
    String exceptionMessage = null;

    User user = new User();
    try {
        require(user::getGender);
    } catch (IllegalArgumentException e) {
        exceptionMessage = e.getMessage();
    }
    Assertions.assertEquals("'gender'需要'MALE|FEMALE'其一", exceptionMessage);
}

@SuppressWarnings("unchecked")
public static <T extends Enum<T>> void require(SerSupp<T> enumSupp) {
    LambdaExecutable executable = LambdaHelper.resolve(enumSupp);
    Enum<T>[] enumConstants = ((Class<Enum<T>>) executable.getReturnType()).getEnumConstants();
    Sf.of(enumSupp.get()).require(() -> new IllegalArgumentException(
            "'"   BeanHelper.getPropertyName(executable.getName())  
                    "'需要'"   Steam.of(enumConstants).map(Enum::name).join("|")   "'其一"));
}

当你使用require(user::getGender)时,如果gendernull,则会抛出异常,并提示:'gender'需要'MALE|FEMALE'其一

这里获取了getGenderlambda方法名称,以及返回值枚举类型,通过遍历枚举的name列举选项,拼接为字符串

0 人点赞