探究 Oracle PDB Application Container (三)

2022-08-19 21:13:09 浏览数 (1)

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Oracle数据库工程师手记:探究 Oracle PDB Application Container (一)

Oracle数据库工程师手记:探究 Oracle PDB Application Container (二)

继续来研究 application container 中的 application 升级问题。

首先,生成 application container 和 application pdb ,以及 application:

代码语言:javascript复制
alter system set db_create_file_dest='/refresh/home/cpdest';
CREATE PLUGGABLE DATABASE appcon1 AS APPLICATION CONTAINER ADMIN USER app_admin IDENTIFIED BY Password1;
  
ALTER PLUGGABLE DATABASE appcon1 OPEN;
ALTER SESSION SET container = appcon1;
  
CREATE PLUGGABLE DATABASE apppdb1 ADMIN USER pdb_admin IDENTIFIED BY Password1;
ALTER PLUGGABLE DATABASE apppdb1 OPEN;
  
  
ALTER SESSION SET container = appcon1;
ALTER PLUGGABLE DATABASE APPLICATION ref_app BEGIN INSTALL '1.0';
  
  
CREATE TABLESPACE ref_app_ts DATAFILE SIZE 1M AUTOEXTEND ON NEXT 1M;
  
CREATE USER ref_app_user IDENTIFIED BY ref_app_user
  DEFAULT TABLESPACE ref_app_ts
  QUOTA UNLIMITED ON ref_app_ts
  CONTAINER=ALL;
  
GRANT CREATE SESSION, CREATE TABLE TO ref_app_user;
  
CREATE TABLE ref_app_user.reference_data SHARING=DATA (
  id          NUMBER,
  description VARCHAR2(50),
  CONSTRAINT t1_pk PRIMARY KEY (id)
);
  
INSERT INTO ref_app_user.reference_data
SELECT level,
       'Description of ' || level
FROM   dual
CONNECT by level <= 5;
COMMIT;
  
  
ALTER PLUGGABLE DATABASE APPLICATION ref_app END INSTALL;

第一次的 application upgrade:

代码语言:javascript复制
ALTER SESSION SET container = appcon1;
  
ALTER PLUGGABLE DATABASE APPLICATION ref_app BEGIN UPGRADE '1.0' TO '1.1';
  
create table tab001(id integer, val varchar2(3));
 
ALTER PLUGGABLE DATABASE APPLICATION ref_app END UPGRADE;

可以,看到生成了一个特殊的 PDB: F139230267_3_1

代码语言:javascript复制
SQL> alter session set container=cdb$root;
 
Session altered.
 
SQL> show pdbs;
 
    CON_ID CON_NAME                       OPEN MODE  RESTRICTED
---------- ------------------------------ ---------- ----------
         2 PDB$SEED                       READ ONLY  NO
         3 PDB193                         MOUNTED
         7 APPCON1                        READ WRITE NO
         9 APPPDB1                        READ WRITE NO
        11 F139230267_3_1                 READ WRITE NO
SQL>

第二次的 application upgrade:

代码语言:javascript复制
ALTER SESSION SET container = appcon1;
  
ALTER PLUGGABLE DATABASE APPLICATION ref_app BEGIN UPGRADE '1.1' TO '1.2';
  
create table tab002(id integer, val varchar2(3));
 
ALTER PLUGGABLE DATABASE APPLICATION ref_app END UPGRADE;

又生成了 一个 特殊PDB: F139230267_3_2

代码语言:javascript复制
SQL> alter session set container=cdb$root;
 
Session altered.
 
SQL> show pdbs;
 
    CON_ID CON_NAME                       OPEN MODE  RESTRICTED
---------- ------------------------------ ---------- ----------
         2 PDB$SEED                       READ ONLY  NO
         3 PDB193                         MOUNTED
         6 F139230267_3_2                 READ WRITE NO
         7 APPCON1                        READ WRITE NO
         9 APPPDB1                        READ WRITE NO
        11 F139230267_3_1                 READ WRITE NO
SQL>

第三次的 application upgrade:

代码语言:javascript复制
ALTER SESSION SET container = appcon1;
  
ALTER PLUGGABLE DATABASE APPLICATION ref_app BEGIN UPGRADE '1.2' TO '1.3';
  
create table tab003(id integer, val varchar2(3));
 
ALTER PLUGGABLE DATABASE APPLICATION ref_app END UPGRADE;

再次生成特殊的 PDB:

代码语言:javascript复制
SQL> alter session set container=cdb$root;
 
Session altered.
 
SQL> show pdbs;
 
    CON_ID CON_NAME                       OPEN MODE  RESTRICTED
---------- ------------------------------ ---------- ----------
         2 PDB$SEED                       READ ONLY  NO
         3 PDB193                         MOUNTED
         5 F139230267_3_3                 READ WRITE NO
         6 F139230267_3_2                 READ WRITE NO
         7 APPCON1                        READ WRITE NO
         9 APPPDB1                        READ WRITE NO
        11 F139230267_3_1                 READ WRITE NO
SQL>

每一次升级 application ,都生成一个新PDB,每次大约 0.7 GB, 对空间的浪费太大了。

代码语言:javascript复制
SQL> select sum(bytes)/1024/1024/1024 from v$datafile where con_id=11;
 
SUM(BYTES)/1024/1024/1024
-------------------------
               .684570313
 
SQL> select sum(bytes)/1024/1024/1024 from v$datafile where con_id=6;
 
SUM(BYTES)/1024/1024/1024
-------------------------
               .694335938
 
SQL>
 
SQL> select sum(bytes)/1024/1024/1024 from v$datafile where con_id=5;
 
SUM(BYTES)/1024/1024/1024
-------------------------
               .694335938
 
SQL>

如何解决?

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