CentOS 6.4安装搭建Tomcat 7

2022-07-01 17:06:03 浏览数 (1)

1.检查Java版本信息

java -version java version "1.7.0_65" OpenJDK Runtime Environment (rhel-2.5.1.2.el6_5-x86_64 u65-b17) OpenJDK 64-Bit Server VM (build 24.65-b04, mixed mode)

如果没有则安装:

yum -y install java-1.7.0-openjdk

2. 下载并解压缩tomcat # cd /tmp # wget http://www.us.apache.org/dist/tomcat/tomcat-7/v7.0.54/bin/apache-tomcat-7.0.54.tar.gz

# tar xzf apache-tomcat-7.0.54.tar.gz # mv apache-tomcat-7.0.54 /usr/local/tomcat7

3. 启动tomcat

# cd /usr/local/tomcat7 # ./bin/startup.sh [输出样例] Using CATALINA_BASE:  /usr/local/tomcat7 Using CATALINA_HOME:  /usr/local/tomcat7 Using CATALINA_TMPDIR: /usr/local/tomcat7/temp Using JRE_HOME:        /opt/jdk1.8.0_05/jre Using CLASSPATH:      /usr/local/tomcat7/bin/bootstrap.jar:/usr/local/tomcat7/bin/tomcat-juli.jar Tomcat started.

4. 访问http://ip:8080

5. 设置用户账户

<role rolename="admin-gui"/> <role rolename="admin-script"/> <role rolename="manager-gui"/> <role rolename="manager-script"/> <role rolename="manager-jmx"/> <role rolename="manager-status"/> <user username="tomcat" password="tomcat" roles="manager-gui,manager-script,manager-jmx,manager-status,admin-script,admin-gui"/>

6. 重启tomcat服务

 # ./bin/shutdown.sh  # ./bin/startup.sh

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