JS手机端touch事件计算滑动距离的方法

2022-03-07 14:37:17 浏览数 (2)

计算手势在手机屏幕上滑动时,手势滑动的距离,代码如下:

function wetherScroll(){ var startX = startY = endX =endY =0; var body=document.getElementsByTagName(“body”); body.bind(‘touchstart’,function(event){ var touch = event.targetTouches[0]; //滑动起点的坐标 startX = touch.pageX; startY = touch.pageY; // console.log(“startX:” startX "," “startY:” startY); }); body.bind(“touchmove”,function(event){ var touch = event.targetTouches[0]; //手势滑动时,手势坐标不断变化,取最后一点的坐标为最终的终点坐标 endX = touch.pageX; endY = touch.pageY; // console.log(“endX:” endX "," “endY:” endY); }) body.bind(“touchend”,function(event){ var distanceX=endX-startX, distanceY=endY - startY; // console.log(“distanceX:” distanceX "," “distanceY:” distanceY); //移动端设备的屏幕宽度 var clientHeight; =document.documentElement.clientHeight; // console.log(clientHeight;0.2); //判断是否滑动了,而不是屏幕上单击了 if(startY!=Math.abs(distanceY)){ //在滑动的距离超过屏幕高度的20%时,做某种操作 if(Math.abs(distanceY)>clientHeight0.2){ //向下滑实行函数someAction1,向上滑实行函数someAction2 distanceY <0 ? someAction1():someAction2(); } } startX = startY = endX =endY =0; }) }

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