2022-04-16:在一个10^6 * 10^6的网格中,
source = sx, sy是出发位置,target = tx, ty是目标位置,
数组blocked是封锁的方格列表,被禁止的方格数量不超过200,
blockedi = xi, yi 表示(xi, yi)的方格是禁止通行的,
每次移动都可以走上、下、左、右四个方向,
但是来到的位置不能在封锁列表blocked上,
同时不允许走出网格。
如果从source能到达target返回 true。否则返回false。
答案2022-04-16:
宽度优先遍历。
n个×,围住n*(n-1)/2个格子。
代码用rust编写。代码如下:
代码语言:rust复制use std::collections::HashSet;
fn main() {
let blocked: Vec<Vec<isize>> = vec![vec![0, 1], vec![1, 0]];
let source: Vec<isize> = vec![0, 0];
let target: Vec<isize> = vec![0, 2];
let ret: bool = isEscapePossible(blocked, source, target);
println!("{}", ret);
}
const offset: isize = 1000000;
fn isEscapePossible(blocked: Vec<Vec<isize>>, source: Vec<isize>, target: Vec<isize>) -> bool {
let n = blocked.len();
let maxPoints: isize = (n * (n - 1) / 2) as isize;
let mut blockSet: HashSet<isize> = vec![].into_iter().collect();
for i in 0..n {
blockSet.insert(blocked[i][0] * offset blocked[i][1]);
}
return bfs(
source[0], source[1], target[0], target[1], maxPoints, &blockSet,
) && bfs(
target[0], target[1], source[0], source[1], maxPoints, &blockSet,
);
}
fn bfs(
fromX: isize,
fromY: isize,
toX: isize,
toY: isize,
maxPoints: isize,
blockSet: &HashSet<isize>,
) -> bool {
let mut visited: HashSet<isize> = vec![].into_iter().collect();
let mut queue: Vec<isize> = Vec::new();
visited.insert(fromX * offset fromY);
queue.push(fromX * offset fromY);
while queue.len() > 0 && (visited.len() as isize <= maxPoints) {
let cur = queue[0];
queue.remove(0);
let curX = cur / offset;
let curY = cur - curX * offset;
if (findAndAdd(curX - 1, curY, toX, toY, blockSet, &mut visited, &mut queue)
|| findAndAdd(curX 1, curY, toX, toY, blockSet, &mut visited, &mut queue)
|| findAndAdd(curX, curY - 1, toX, toY, blockSet, &mut visited, &mut queue)
|| findAndAdd(curX, curY 1, toX, toY, blockSet, &mut visited, &mut queue))
{
return true;
}
}
return visited.len() as isize > maxPoints;
}
// 来到的点,(row, col)
// 要寻找的目标点,toX, toY
// HashSet<Long> blockSet存着不能走的格子!障碍点!
// HashSet<Long> visited, Queue<Long> queue 为了宽度优先遍历服务的!
// visited,已经处理过的点,请不要重复的放入queue
// 如果已经到达了(toX, toY)
fn findAndAdd(
row: isize,
col: isize,
toX: isize,
toY: isize,
blockSet: &HashSet<isize>,
visited: &mut HashSet<isize>,
queue: &mut Vec<isize>,
) -> bool {
if (row < 0 || row == offset || col < 0 || col == offset) {
return false;
}
if (row == toX && col == toY) {
return true;
}
let value = row * offset col;
if !blockSet.contains(&value) && !visited.contains(&value) {
visited.insert(value);
queue.push(value);
}
return false;
}
执行结果如下:
左神java代码