python用来获得图片exif信息的库代码

2021-11-03 13:12:56 浏览数 (3)

下面的代码演示的是调用方法。

代码语言:javascript复制
# library test/debug function (dump given files)
if name == 'main':
    import sys
    import getopt

# parse command line options/arguments
try:
    opts, args = getopt.getopt(sys.argv[1:], "hqsdt:v", ["help", "quick", "strict", "debug", "stop-tag="])
except getopt.GetoptError:
    usage(2)
if args == []:
    usage(2)
detailed = True
stop_tag = 'UNDEF'
debug = False
strict = False
for o, a in opts:
    if o in ("-h", "--help"):
        usage(0)
    if o in ("-q", "--quick"):
        detailed = False
    if o in ("-t", "--stop-tag"):
        stop_tag = a
    if o in ("-s", "--strict"):
        strict = True
    if o in ("-d", "--debug"):
        debug = True

# output info for each file
for filename in args:
    try:
        file=open(filename, 'rb')
    except:
        print "'%s' is unreadablen"%filename
        continue
    print filename   ':'
    # get the tags
    data = process_file(file, stop_tag=stop_tag, details=detailed, strict=strict, debug=debug)
    if not data:
        print 'No EXIF information found'
        continue

    x=data.keys()
    x.sort()
    for i in x:
        if i in ('JPEGThumbnail', 'TIFFThumbnail'):
            continue
        try:
            print '   %s (%s): %s' % 
                  (i, FIELD_TYPES[data[i].field_type][2], data[i].printable)
        except:
            print 'error', i, '"', data[i], '"'
    if 'JPEGThumbnail' in data:
        print 'File has JPEG thumbnail'
    print</pre> 

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