本设计仅用到了zynq的ps端。利用串口完成计算数据的输入输出实现简易计算器。
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/*
* helloworld.c: simple test application
*
* This application configures UART 16550 to baud rate 9600.
* PS7 UART (Zynq) is not initialized by this application, since
* bootrom/bsp configures it to baud rate 115200
*
* ------------------------------------------------
* | UART TYPE BAUD RATE |
* ------------------------------------------------
* uartns550 9600
* uartlite Configurable only in HW design
* ps7_uart 115200 (configured by bootrom/bsp)
*/
#include <stdio.h>
#include "platform.h"
#include "xil_printf.h"
#include "math.h"
double calculator();
int main()
{
init_platform();
print("Hello Worldnr");
calculator();
cleanup_platform();
return 0;
}
double calculator()
{
// 分别存放第一个操作数和第二个操作数以及结果的变量
double x1,x2,result;
// 存放运算符的变量
char m;
while(1)
{
printf("请输入第一个数：n");
// 下面这得注意，接收double型的数据得用lf%，接收float用f%
scanf("%lf",&x1);
printf("请输入运算操作（ - * /）：n");
m = getchar();
printf("n");
printf("请输入第二个数：n");
scanf("%lf",&x2);
switch(m)
{
case ' ':
printf("加法n");
result = x1 x2;
printf("%lf %lf = %lfn",x1,x2,result);
break;
case '-':
printf("减法n");
result = x1 - x2;
printf("%lf - %lf = %lfn",x1,x2,result);
break;
case '*':
printf("乘法n");
result = x1 * x2;
printf("%lf * %lf = %lfn",x1,x2,result);
break;
case '/':
printf("除法n");
if(x2 == 0)
{
printf("除数不能为0.n");
}
else
{
result = x1 / x2;
printf("%lf / %lf = %lfn",x1,x2,result);
}
break;
default:
break;
}
}
return 0.0;
}
调试：
