Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead.
For example, given the array 2,3,1,2,4,3 and s = 7,
the subarray 4,3 has the minimal length under the problem constraint.
More practice:
If you have figured out the O(n) solution, try coding another solution of which the time complexity is O(n log n).
代码语言:txt复制定义两个指针,st和ed。如果sum>=s,sum从前面元素开始减;如果sum< s,ed 。
public int minSubArrayLen(int s, int[] nums) {
int sum = 0;
int st = 0;
int min = Integer.MAX_VALUE;
for (int i = 0; i < nums.length; i ) {
sum = nums[i];
if (sum >= s) {
while (sum - nums[st] >= s) {
sum -= nums[st ];
}
min = Math.min(min, i - st 1);
}
}
if (min > nums.length) {
return 0;
}
return min;
}