Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n.
For example, given n = 12, return 3 because 12 = 4 4 4; given n = 13, return 2 because 13 = 4 9.
动态规划,求解最优化问题,自底向上。
代码语言:javascript复制 public int numSquares(int n) {
int[] dp = new int[n 1];
Arrays.fill(dp, Integer.MAX_VALUE);
// 将所有平方数置1
for (int i = 0; i * i <= n; i ) {
dp[i * i] = 1;
}
for (int a = 1; a <= n; a ) {
for (int b = 1; a b * b <= n; b ) {
// 取较小值,a b * b也可能是平方数
dp[a b * b] = Math.min(dp[a] 1, dp[a b * b]);
}
}
return dp[n];
}