Given a string containing only digits, restore it by returning all possible valid IP address combinations.
For example:
Given "25525511135",
return "255.255.11.135", "255.255.111.35". (Order does not matter)
代码语言:javascript复制 List<String> rt = new ArrayList<String>();
String[] stack = new String[4];
public List<String> restoreIpAddresses(String s) {
if (s == null || s.length() == 0) {
return new ArrayList<String>();
}
dfs(s, 0, 0);
return rt;
}
/**
*
* @param s
* @param p
* :指针
* @param pstack
* :stack的下标
*/
public void dfs(String s, int p, int pstack) {
if (pstack == 4) {
// 如果stack长度为4,且s的字符全部用上
// 则stack[0...3]存了一个结果
if (p >= s.length()) {
String ip = String.join(".", stack);
rt.add(ip);
}
return;
}
// 获取1~3个字符
for (int i = 1; i <= 3; i ) {
// 如果超过字符串长度,返回
if (p i > s.length()) {
return;
}
// 若选取的第一个字符是0,则停止选取
if (i > 1 && s.charAt(p) == '0') {
continue;
}
String number = s.substring(p, p i);
// 如果number<=255,递归
if (Integer.parseInt(number) <= 255) {
stack[pstack] = number;
dfs(s, p i, pstack 1);
}
}
}