Leetcode 题目解析之 Restore IP Addresses

2022-02-13 15:23:19 浏览数 (3)

Given a string containing only digits, restore it by returning all possible valid IP address combinations.

For example:

Given "25525511135",

return "255.255.11.135", "255.255.111.35". (Order does not matter)

代码语言:javascript复制
    List<String> rt = new ArrayList<String>();
    String[] stack = new String[4];
    public List<String> restoreIpAddresses(String s) {
        if (s == null || s.length() == 0) {
            return new ArrayList<String>();
        }
        dfs(s, 0, 0);
        return rt;
    }
    /**
     * 
     * @param s
     * @param p
     *            :指针
     * @param pstack
     *            :stack的下标
     */
    public void dfs(String s, int p, int pstack) {
        if (pstack == 4) {
            // 如果stack长度为4,且s的字符全部用上
            // 则stack[0...3]存了一个结果
            if (p >= s.length()) {
                String ip = String.join(".", stack);
                rt.add(ip);
            }
            return;
        }
        // 获取1~3个字符
        for (int i = 1; i <= 3; i  ) {
            // 如果超过字符串长度,返回
            if (p   i > s.length()) {
                return;
            }
            // 若选取的第一个字符是0,则停止选取
            if (i > 1 && s.charAt(p) == '0') {
                continue;
            }
            String number = s.substring(p, p   i);
            // 如果number<=255,递归
            if (Integer.parseInt(number) <= 255) {
                stack[pstack] = number;
                dfs(s, p   i, pstack   1);
            }
        }
    }

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