1. Description
2. Solution
**解析:**Version 1,分别求连续子数组的最大值与最小值,然后取二者绝对值较大的一个即可。
- Version 1
class Solution:
def maxAbsoluteSum(self, nums: List[int]) -> int:
n = len(nums)
pos = 0
neg = 0
maximum = 0
for i in range(n):
pos = nums[i]
neg = nums[i]
maximum = max(maximum, abs(pos), abs(neg))
pos = max(0, pos)
neg = min(0, neg)
return maximum
Reference
- https://leetcode.com/problems/maximum-absolute-sum-of-any-subarray/