Fortune-telling with camomile
Problem Description
Masha loves Petya. The following question gives her no rest: does Petya love her too? The best way to find this out is a fortune-telling. There are plenty ways of fortune predicting, but Masha prefers fortune-telling with camomile more than others. It’s rules are simple. You should take camomile into the right hand and start picking petals one by one. After each petal you should pronounce one phrase from the predefined list. Such phrases like “loves”, “doesn’t love”, “loves sincerely”, “doubts”, “wants to date”, “laughs” are usually used. Phrases are pronounced from the first to the last. The list of phrases is cyclic, so after the last phrase you should pronounce the first one. The phrase that you pronounce after the last petal will be an answer.
Since Masha doesn’t want to go to the forest and look for camomiles, she asks you to write the program which will simulate the process.
Input
First line of the input file contains two integer numbers N and M (1 <= N <= 100, 1 <= M <= 100), the number of petals and the number of phrases. Each of the following M lines contains one phrase. Phrases consist only of latin letters and their lengths are between 1 and 100.
Output
Output the resulting phrase.
Example(s)
sample input | sample output |
|---|---|
6 4 | |
lovesdoesntsincerelydoubtsdoesnt |
|sample input|sample output| |9 3| |loves doesnt hates hates|
Solution
代码语言：javascript复制#include <bits/stdc .h>
int main() {
std::ios::sync_with_stdio(false);
int n{};
int m{};
std::cin >> n >> m;
std::vector<std::string> dict(m, "");
for(int i = 0; i < m; i ) {
std::cin >> dict[i];
}
std::cout << dict[(n - 1) % m];
return 0;
}
