LeetCode 0010 - Regular Expression Matching

Regular Expression Matching

Desicription

Implement regular expression matching with support for '.' and '*'.

代码语言：javascript复制

'.' Matches any single character.
'*' Matches zero or more of the preceding element.

The matching should cover the entire input string (not partial).

The function prototype should be:
bool isMatch(const char *s, const char *p)

Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa", "a*") → true
isMatch("aa", ".*") → true
isMatch("ab", ".*") → true
isMatch("aab", "c*a*b") → true

Solution

代码语言：javascript复制

class Solution {
public:
    bool isMatch(string s, string p) {
        if(p.empty())
            return s.empty();
        if(p[1] == '*')
            return isMatch(s, p.substr(2)) || (!s.empty() && (s[0] == p[0] || p[0] == '.') && isMatch(s.substr(1), p));
        else
            return !s.empty() && (s[0] == p[0] || p[0] == '.') && isMatch(s.substr(1), p.substr(1));
    }
};

express

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