Minimum Path Sum
Desicription
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
Example 1:
代码语言：javascript复制[[1,3,1],
[1,5,1],
[4,2,1]]Given the above grid map, return 7. Because the path 1→3→1→1→1 minimizes the sum.
Solution
代码语言：javascript复制class Solution {
public:
int minPathSum(vector<vector<int>>& grid) {
int n = grid.size();
int m = grid[0].size();
vector<int> dp(m, 0);
dp[0] = grid[0][0];
for(int i = 1; i < m; i )
dp[i] = grid[0][i] dp[i-1];
for(int i = 1; i < n; i ){
dp[0] = grid[i][0];
for(int j = 1; j < m; j )
dp[j] = min(dp[j], dp[j-1]) grid[i][j];
}
return dp[m-1];
}
};
