Interleaving String
Desicription
Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2.
For example,
Given:
s1 = "aabcc",
s2 = "dbbca",
When s3 = "aadbbcbcac", return true.
When s3 = "aadbbbaccc", return false.
Solution
代码语言：javascript复制class Solution {
public:
bool isInterleave(string s1, string s2, string s3) {
if(s1.size() s2.size() != s3.size())
return 0;
vector<vector<bool>> table(s1.size() 1, vector<bool>(s2.size() 1, 0));
for(int i = 0; i <= s1.size(); i ) {
for(int j = 0; j <= s2.size(); j ){
if(!i && !j)
table[i][j] = 1;
else if(!i)
table[i][j] = (table[i][j-1] && s2[j-1] == s3[i j-1]);
else if(!j)
table[i][j] = (table[i-1][j] && s1[i-1] == s3[i j-1]);
else
table[i][j] = ((table[i-1][j] && s1[i-1] == s3[i j-1]) || (table[i][j-1] && s2[j-1] == s3[i j-1]));
}
}
return table[s1.size()][s2.size()];
}
};
