LeetCode 0099 - Recover Binary Search Tree

Recover Binary Search Tree

Desicription

Two elements of a binary search tree (BST) are swapped by mistake.

Recover the tree without changing its structure.

Note: A solution using O(n) space is pretty straight forward. Could you devise a constant space solution?

Solution

代码语言：javascript复制

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
private:
    TreeNode* pre = new TreeNode(INT_MIN);
    TreeNode* first = NULL;
    TreeNode* second = NULL;

    void searchTree(TreeNode* root) {
        if(!root)
            return ;
        searchTree(root->left);
        if(!first && pre->val >= root->val)
            first = pre;
        if(first && pre->val >= root->val)
            second = root;
        pre = root;
        searchTree(root->right);
    }
public:
    void recoverTree(TreeNode* root) {
        searchTree(root);
        swap(first->val, second->val);
    }
};

binary search space structure tree

0 人点赞