Patching Array
Desicription
Given a sorted positive integer array nums and an integer n, add/patch elements to the array such that any number in range [1, n] inclusive can be formed by the sum of some elements in the array. Return the minimum number of patches required.
Example 1:
代码语言：javascript复制Input: nums = [1,3], n = 6
Output: 1
Explanation:
Combinations of nums are [1], [3], [1,3], which form possible sums of: 1, 3, 4.
Now if we add/patch 2 to nums, the combinations are: [1], [2], [3], [1,3], [2,3], [1,2,3].
Possible sums are 1, 2, 3, 4, 5, 6, which now covers the range [1, 6].
So we only need 1 patch.Example 2:
代码语言：javascript复制Input: nums = [1,5,10], n = 20
Output: 2
Explanation: The two patches can be [2, 4].Example 3:
代码语言：javascript复制Input: nums = [1,2,2], n = 5
Output: 0Solution
代码语言：javascript复制class Solution {
public:
int minPatches(std::vector<int>& nums, int n) {
int res = 0;
int index = 0;
long long miss = 1;
while(miss <= n) {
if(index < nums.size() && nums[index] <= miss) {
miss = nums[index ];
} else {
miss = miss;
res ;
}
}
return res;
}
};
