LeetCode 0319 - Bulb Switcher

2021-08-11 11:57:02 浏览数 (3)

Bulb Switcher

Desicription

There are n bulbs that are initially off. You first turn on all the bulbs. Then, you turn off every second bulb. On the third round, you toggle every third bulb (turning on if it’s off or turning off if it’s on). For the i-th round, you toggle every i bulb. For the n-th round, you only toggle the last bulb. Find how many bulbs are on after n rounds.

Example:

代码语言:javascript复制
Input: 3
Output: 1 
Explanation: 
At first, the three bulbs are [off, off, off].
After first round, the three bulbs are [on, on, on].
After second round, the three bulbs are [on, off, on].
After third round, the three bulbs are [on, off, off]. 

So you should return 1, because there is only one bulb is on.

Solution

代码语言:javascript复制
class Solution {
public:
    int bulbSwitch(int n) {
        return sqrt(n);
    }
};

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