Product of Array Except Self
Desicription
Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i].
Example:
代码语言：javascript复制Input: [1,2,3,4]
Output: [24,12,8,6]Note: Please solve it without division and in O(n).
Follow up: Could you solve it with constant space complexity? (The output array does not count as extra space for the purpose of space complexity analysis.)
Solution
代码语言：javascript复制class Solution {
public:
vector<int> productExceptSelf(vector<int>& nums) {
vector<int> pre(nums.size(), 1);
vector<int> suf(nums.size(), 1);
vector<int> res(nums.size(), 1);
for(int i = 0; i < nums.size(); i ) {
pre[i] = i ? pre[i - 1] * nums[i] : nums[i];
}
for(int i = nums.size() - 1; i > 0; i--) {
suf[i] = i == nums.size() - 1 ? nums[i] : suf[i 1] * nums[i];
}
for(int i = 0; i < nums.size(); i ) {
if(i == 0) {
res[i] = suf[i 1];
} else if(i == nums.size() - 1) {
res[i] = pre[i - 1];
} else {
res[i] = pre[i - 1] * suf[i 1];
}
}
return res;
}
};
