House Robber
Desicription
You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.
Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.
Example 1:
代码语言：javascript复制Input: [1,2,3,1]
Output: 4
Explanation: Rob house 1 (money = 1) and then rob house 3 (money = 3).
Total amount you can rob = 1 3 = 4.Example 2:
代码语言：javascript复制Input: [2,7,9,3,1]
Output: 12
Explanation: Rob house 1 (money = 2), rob house 3 (money = 9) and rob house 5 (money = 1).
Total amount you can rob = 2 9 1 = 12.Solution
代码语言：javascript复制class Solution {
public:
int rob(vector<int>& nums) {
int a = 0;
int b = 0;
for(int i = 0; i < nums.size(); i ) {
if(i & 1)
a = max(a nums[i], b);
else
b = max(b nums[i], a);
}
return max(a, b);
}
};
