1. Description
2. Solution
**解析:**Version 1,先将年、月、日分离出来,然后根据月份和日期累加天数,最后判断时闰年的话总天数加1
。
- Version 1
class Solution:
def dayOfYear(self, date: str) -> int:
year, month, day = map(int, date.split('-'))
months = [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
days = day
for i in range(month):
days = months[i]
if month > 2 and (year % 400 == 0 or (year % 4 == 0 and year % 100 != 0)):
days = 1
return days
Reference
- https://leetcode.com/problems/day-of-the-year/