0x00 设置堆栈
栈顶指针按位与之后，将栈桢以16字节的大小对齐：
代码语言：javascript复制push rbp ;store rbp original state
mov rbp, rsp ;set stack base point to current stack top
sub rsp, 60h ;reserve stack space for called functions
and rsp, 0fffffffffffffff0h ;make sure stack 16-byte aligned或者
代码语言：javascript复制push rsi ; Preserve RSI since we're stomping on it
mov rsi, rsp ; Save the value of RSP so it can be restored
and rsp, 0FFFFFFFFFFFFFFF0h ; Align RSP to 16 bytes
sub rsp, 020h ; Allocate homing space for ExecutePayload我对内存对齐的理解：
把栈想象成一个积木堆成的楼，32位里每个积木能容纳4字节（32位），楼层高2的32次方，比如现在你在13楼里操作，发现13楼里堆了一部分东西，但是没有满，此时你有两种选择：继续在这楼里堆你的东西、再往上走几层重新开始堆。 第一种：继续在这楼里堆你的东西，当你堆的东西这层撑不下会移到下一层继续堆，此时让你找到最开始堆的东西的位置时候，你就要大费周章了，因为你要说在13楼哪个位置（具体到那个bit上），这就很影响寻址效率 如果是往上走走，从一个空楼层开始的地方堆的话，比如到了16楼，这时候不管你堆多少你都可以很方便的走到16楼，这就是第二种 现在16楼开始的地方就是你的东西，虽然牺牲了中间14楼15楼的空间，但是提高了效率，这就是内存里的空间换时间 对齐的方式有很多，上面说的就是以一层楼（4字节，32位）为对齐方式 很明显，如果13层楼只占用了1个字节（8位），那么你的东西至少会放在14楼开始的地方，但是你的东西只有2字节（16位），13楼足以容纳，却跑到了14楼，此时空间牺牲的就有点大了 就要适当缩小对齐单位，从4字节（32位）缩到2字节（16位），这时候你的东西就可以放在13楼里了，而且找到你的东西起始位置也很简单，从13楼开始的地方每隔2字节（16位）看一下，发现第二个2字节就是自己开始存东西的地方，很方便快速 对应到x64里也很简单，一层楼的大小变成了8字节（64位），楼高2的64次方，esp就是指向的当前楼层，按16个字节对齐的话，就是按两层楼对齐，两层楼里尽管只要有一点点东西，你的东西也要从后面两层重新堆 其实楼高多少，要和栈指针寄存器的容量相关
0x01 获取kernel32/LoadLibraryA基址
r12 存储 kernel32 基址，通过 GetProcessAddress 将 LoadLibraryA 函数地址存储在 rax：
代码语言：javascript复制format PE64 GUI 6.0
entry main
section '.text' executable
main:
;write your code here
xor rax, rax
sub rsp, 28h ;reserve stack space for called function
and rsp, 0fffffffffffffff0h ;make sure stack 16-byte aligned
mov r12, [gs:60h] ;peb
mov r12, [r12 0x18] ;peb->ldr
mov r12, [r12 0x20] ;peb->ldr->InMemoryOrderModuleList
mov r12, [r12] ;2st entry
mov r15, [r12 0x20] ;ntdll.dll base address!
mov r12, [r12] ;3nd entry
mov r12, [r12 0x20] ;kernel32.dll base address!
mov rdx, 0xec0e4e8e ;LoadLibraryA hash from ror13
mov rcx, r12 ;kernel32 base address
call GetProcessAddress
ret
;Hashing section to resolve a function address
GetProcessAddress:
mov r13, rcx ;base address of dll loaded
mov eax, [r13d 0x3c] ;skip DOS header and go to PE header
mov r14d, [r13d eax 0x88] ;0x88 offset from the PE header is the export table.
add r14d, r13d ;make the export table an absolute base address and put it in r14d.
mov r10d, [r14d 0x18] ;go into the export table and get the numberOfNames
mov ebx, [r14d 0x20] ;get the AddressOfNames offset.
add ebx, r13d ;AddressofNames base.
find_function_loop:
jecxz find_function_finished ;if ecx is zero, quit :( nothing found.
dec r10d ;dec ECX by one for the loop until a match/none are found
mov esi, [ebx r10d * 4] ;get a name to play with from the export table.
add esi, r13d ;esi is now the current name to search on.
find_hashes:
xor edi, edi
xor eax, eax
cld
continue_hashing:
lodsb ;get into al from esi
test al, al ;is the end of string resarched?
jz compute_hash_finished
ror dword edi, 0xd ;ROR13 for hash calculation!
add edi, eax
jmp continue_hashing
compute_hash_finished:
cmp edi, edx ;edx has the function hash
jnz find_function_loop ;didn't match, keep trying!
mov ebx, [r14d 0x24] ;put the address of the ordinal table and put it in ebx.
add ebx, r13d ;absolute address
xor ecx, ecx ;ensure ecx is 0'd.
mov cx, [ebx 2 * r10d] ;ordinal = 2 bytes. Get the current ordinal and put it in cx. ECX was our counter for which # we were in.
mov ebx, [r14d 0x1c] ;extract the address table offset
add ebx, r13d ;put absolute address in EBX.
mov eax, [ebx 4 * ecx] ;relative address
add eax, r13d
find_function_finished:
ret编译：fasm win64_msg.asm
使用 x64dbg 调试查看到获取地址成功：
0x02 GetProcAddreass 获取 API 地址
这个函数里为什么要用 hash 比对，也可以直接 API 名字比对，但是汇编比较麻烦，并且会在生成的二进制文件中出现字符串特征，所以用 hash 比对。
通过对 kernel32.dll 的导出表中记录的 API name 进行 hash 对比，可以找到 LoadLibraryA API 基址，然后就可以利用该函数加载其他 dll 了。
弹消息框需要的是 user32.dll 的 MessageBox，所以我们需要先载入 user32.dll，之后使用上面同样的 hash 比对方法获取 MessageBox API 的地址，关于 API hash怎么获取，可以参考：https://github.com/ihack4falafel/ROR13HashGenerato。
0x03 获取 MessageBoxA 地址并弹框
最终代码：
代码语言：javascript复制format binary
use64
;format PE64 GUI 6.0
;entry main
;section '.text' executable
;main:
;find kernel32 dll base address from peb
push rbp
mov rbp, rsp
sub rsp, 60h ; reserve stack space for called function
and rsp, 0fffffffffffffff0h ; make sure stack 16-byte aligned
mov r12, [gs:60h] ; peb
mov r12, [r12 0x18] ; peb->ldr
mov r12, [r12 0x20] ; peb->ldr->InMemoryOrderModuleList
mov r12, [r12] ; 2st entry
mov r15, [r12 0x20] ; ntdll.dll base address!
mov r12, [r12] ; 3nd entry
mov r12, [r12 0x20] ; kernel32.dll base address!
;find LoadLibraryA API address from kernel32.dll
mov rdx, 0xec0e4e8e ; LoadLibraryA hash from ror13
mov rcx, r12 ; kernel32 base address
call GetProcessAddress ; LoadLibraryA address -> rax
mov [rbp-30h], rax
;use LoadLibraryA to load user32.dll
jmp GetUser32String ; call/pop get 'user32.dll' string
jmpFromGetUser32String:
pop rcx ; rcx <- esp <- 'user32.dll'
call rax ; call LoadLibraryA, store base address to rax
;find MessageBoxA API address from user32.dll
mov rdx, 0xBC4DA2A8 ; MessageBoxA hash from ror13
mov rcx, rax ; user32 base address
call GetProcessAddress ; MessageBoxA address -> rax
;call MessageBoxA API to display message dialog
mov r9, 0 ; MS_BUTTEN_OK
jmp GetTitleString ; store title string to stack
jmpFromGetTitleString:
pop r8 ; get title string from stack top
jmp GetTextString ; store text string to stack
jmpFromGetTextString:
pop rdx ; get text string from stack top
mov rcx, 0 ; hWnd
call rax ; call MessageBoxA
;find ExitThread API address from kernel32
;mov rdx, 0x60E0CEEF ; ExitThread hash from ror13
;mov rcx, r12 ; kernel32 base address
;call GetProcessAddress ; ExitThread address -> rax
;load ntdll.dll
mov rax, [rbp-30h] ; rax = address of LoadLibraryA
jmp GetNtdllString
jmpFromGetNtdllString:
pop rcx
call rax
;find RltExitUserThread API address from ntdll.dll
mov rdx, 0xFF7F061A
mov rcx, rax
call GetProcessAddress
;call RltExitUserThread API to exit thread
mov rcx, 0 ; thread exit code = 0
call rax ; call ExitThread
;add rsp, 60h ; restore stack
;pop rbp
;ret
GetNtdllString:
call jmpFromGetNtdllString
db 'ntdll.dll',0
GetUser32String:
call jmpFromGetUser32String
db 'user32.dll',0
GetTitleString:
call jmpFromGetTitleString
db 'ERROR',0
GetTextString:
call jmpFromGetTextString
db 'Hello World!',0
;Hashing section to resolve a function address
GetProcessAddress:
mov r13, rcx ;base address of dll loaded
mov eax, [r13d 0x3c] ;skip DOS header and go to PE header
mov r14d, [r13d eax 0x88] ;0x88 offset from the PE header is the export table.
add r14d, r13d ;make the export table an absolute base address and put it in r14d.
mov r10d, [r14d 0x18] ;go into the export table and get the numberOfNames
mov ebx, [r14d 0x20] ;get the AddressOfNames offset.
add ebx, r13d ;AddressofNames base.
find_function_loop:
jecxz find_function_finished ;if ecx is zero, quit :( nothing found.
dec r10d ;dec ECX by one for the loop until a match/none are found
mov esi, [ebx r10d * 4] ;get a name to play with from the export table.
add esi, r13d ;esi is now the current name to search on.
find_hashes:
xor edi, edi
xor eax, eax
cld
continue_hashing:
lodsb ;get into al from esi
test al, al ;is the end of string resarched?
jz compute_hash_finished
ror dword edi, 0xd ;ROR13 for hash calculation!
add edi, eax
jmp continue_hashing
compute_hash_finished:
cmp edi, edx ;edx has the function hash
jnz find_function_loop ;didn't match, keep trying!
mov ebx, [r14d 0x24] ;put the address of the ordinal table and put it in ebx.
add ebx, r13d ;absolute address
xor ecx, ecx ;ensure ecx is 0'd.
mov cx, [ebx 2 * r10d] ;ordinal = 2 bytes. Get the current ordinal and put it in cx. ECX was our counter for which # we were in.
mov ebx, [r14d 0x1c] ;extract the address table offset
add ebx, r13d ;put absolute address in EBX.
mov eax, [ebx 4 * ecx] ;relative address
add eax, r13d
find_function_finished:
ret其中 format binary 和 use64 表示生成 64 位的 shellcode，如果注释掉，如果换成下面我注释的那四行代表生成 64 位 exe。
加载 shellcode，可以自己写，也可以用这个项目里的 runshc64.exe 测试一下 https://github.com/hasherezade/pe_to_shellcode。
0x04 shellcode 退出
shellcode 执行完相应的功能，退出的方式有以下几种：
- 调用 kernel32!ExitProcess，适合直接终止整个程序
- 调用 kernel32!ExitThread，适合终止线程
- ret，正常返回，结束程序由主程序负责
测试线程退出的时候发现，直接汇编调用 kernel32!ExitThread 会导致程序 crash：
;find ExitThread API address from kernel32
mov rdx, 0x60E0CEEF ; ExitThread hash from ror13
mov rcx, r12 ; kernel32 base address
call GetProcessAddress ; ExitThread address -> rax
mov rcx, 0 ; thread exit code = 0
call rax ; call ExitThread
由于 kernel32!ExitThread 最终会重定向到 ntdll!RtlExitUserThread 所以改用这个试试：
;load ntdll.dll
mov rax, [rbp-30h] ; rax = address of LoadLibraryA
jmp GetNtdllString
jmpFromGetNtdllString:
pop rcx
call rax
;find RltExitUserThread API address from ntdll.dll
mov rdx, 0xFF7F061A
mov rcx, rax
call GetProcessAddress
;call RltExitUserThread API to exit thread
mov rcx, 0 ; thread exit code = 0
call rax ; call ExitThread这个就没有问题，很神奇，同时简单看了一下 msf 生成 MessageBox 汇编的代码，貌似和 Windows 版本有关系。
还有一个问题，就是如果不使用 API 退出，只是 ret 的话主进程并不能退出，搞不懂：
代码语言：javascript复制xor rax, rax
add rsp, 60h ; restore stack
pop rbp
ret由 x64dbg 调了一下，发现是堆栈不平衡导致的，为什么会堆栈不平衡？
代码语言：javascript复制push rbp
mov rbp, rsp
sub rsp, 60h ; reserve stack space for called function
and rsp, 0fffffffffffffff0h ; make sure stack 16-byte aligned
;;;;;;;;;;;;
xor rax, rax
add rsp, 60h ; restore stack
pop rbp
ret这是由于 and rsp, 0fffffffffffffff0h 这句导致的，在某些情况下会导致 rsp - 8。知道问题根源之后，就想把这句去掉，去掉之后发现 MessageBoxA 调用过程内存访问异常了，纳闷。
最后想了个办法，在 and 指令之前先用 rbp 保存一下当前栈顶，然后到结束直接恢复回去：
代码语言：javascript复制push rbp ; save rbp original state
mov rbp, rsp
sub rsp, 60h ; reserve stack space for called function
and rsp, 0fffffffffffffff0h ; make sure stack 16-byte aligned
;;;;;;;;;;;;
xor rax, rax
mov rsp, rbp ; resotre rsp
pop rbp ; restore rbp
ret这个解决之后，返回到调用 shellcode 之后的地方继续执行，会出现访问异常，这个调了一下，发现是 shellcode 执行过程把 rsi 寄存器改了，所以解决办法就是像 rbp 一样，先保存一下，最后恢复回去：
代码语言：javascript复制push rsi ; save rbp state
push rbp ; save rbp state
mov rbp, rsp
sub rsp, 60h ; reserve stack space for called function
and rsp, 0fffffffffffffff0h ; make sure stack 16-byte aligned
;;;;;;;;;;;;
xor rax, rax ; return 0
mov rsp, rbp ; resotre rsp
pop rbp ; restore rbp
pop rsi ; restore rsi
ret最后，完美运行！
0x05 中文弹框
改成 MessageBoxW，他的 hash 是 0xBC4DA2BE，然后使用 fasm 提供的 du 指令，需要包含 encodingutf8.inc：
include 'encodingutf8.inc'
format binary
use64
;format PE64 GUI 6.0
;entry main
;section '.text' executable
;main:
;find kernel32 dll base address from peb
push r12
push rdi
push rdx
push rcx
push rbx
push rbp
mov rbp, rsp
sub rsp, 68h ; reserve stack space for called function
and rsp, 0fffffffffffffff0h ; make sure stack 16-byte aligned
mov r12, [gs:60h] ; peb
mov r12, [r12 0x18] ; peb->ldr
mov r12, [r12 0x20] ; peb->ldr->InMemoryOrderModuleList
mov r12, [r12] ; 2st entry
mov r15, [r12 0x20] ; ntdll.dll base address!
mov r12, [r12] ; 3nd entry
mov r12, [r12 0x20] ; kernel32.dll base address!
;find LoadLibraryA API address from kernel32.dll
mov rdx, 0xec0e4e8e ; LoadLibraryA hash from ror13
mov rcx, r12 ; kernel32 base address
call GetProcessAddress ; LoadLibraryA address -> rax
mov [rbp-30h], rax
;use LoadLibraryA to load user32.dll
jmp GetUser32String ; call/pop get 'user32.dll' string
jmpFromGetUser32String:
pop rcx ; rcx <- esp <- 'user32.dll'
call rax ; call LoadLibraryA, store base address to rax
;find MessageBoxW API address from user32.dll
mov rdx, 0xBC4DA2BE ; MessageBoxW hash from ror13
mov rcx, rax ; user32 base address
call GetProcessAddress ; MessageBoxW address -> rax
;call MessageBoxW API to display message dialog
mov r9, 0 ; MS_BUTTEN_OK
jmp GetTitleString ; store title string to stack
jmpFromGetTitleString:
pop r8 ; get title string from stack top
jmp GetTextString ; store text string to stack
jmpFromGetTextString:
pop rdx ; get text string from stack top
mov rcx, 0 ; hWnd
call rax ; call MessageBoxW
xor rax, rax
mov rsp, rbp
pop rbp
pop rbx
pop rcx
pop rdx
pop rdi
pop r12
ret
GetUser32String:
call jmpFromGetUser32String
db 'user32.dll',0
GetTitleString:
call jmpFromGetTitleString
du 'ERROR',0
GetTextString:
call jmpFromGetTextString
du '资源加载失败！',0
;Hashing section to resolve a function address
GetProcessAddress:
mov r13, rcx ;base address of dll loaded
mov eax, [r13d 0x3c] ;skip DOS header and go to PE header
mov r14d, [r13d eax 0x88] ;0x88 offset from the PE header is the export table.
add r14d, r13d ;make the export table an absolute base address and put it in r14d.
mov r10d, [r14d 0x18] ;go into the export table and get the numberOfNames
mov ebx, [r14d 0x20] ;get the AddressOfNames offset.
add ebx, r13d ;AddressofNames base.
find_function_loop:
jecxz find_function_finished ;if ecx is zero, quit :( nothing found.
dec r10d ;dec ECX by one for the loop until a match/none are found
mov esi, [ebx r10d * 4] ;get a name to play with from the export table.
add esi, r13d ;esi is now the current name to search on.
find_hashes:
xor edi, edi
xor eax, eax
cld
continue_hashing:
lodsb ;get into al from esi
test al, al ;is the end of string resarched?
jz compute_hash_finished
ror dword edi, 0xd ;ROR13 for hash calculation!
add edi, eax
jmp continue_hashing
compute_hash_finished:
cmp edi, edx ;edx has the function hash
jnz find_function_loop ;didn't match, keep trying!
mov ebx, [r14d 0x24] ;put the address of the ordinal table and put it in ebx.
add ebx, r13d ;absolute address
xor ecx, ecx ;ensure ecx is 0'd.
mov cx, [ebx 2 * r10d] ;ordinal = 2 bytes. Get the current ordinal and put it in cx. ECX was our counter for which # we were in.
mov ebx, [r14d 0x1c] ;extract the address table offset
add ebx, r13d ;put absolute address in EBX.
mov eax, [ebx 4 * ecx] ;relative address
add eax, r13d
find_function_finished:
ret显示正常，nice！
