1. Description
2. Solution
- Version 1
class Solution:
def countBinarySubstrings(self, s: str) -> int:
length = len(s)
count = 0
pre = 0
curr = 1
for i in range(1, length):
if s[i] == s[i - 1]:
curr = 1
else:
count = min(pre, curr)
pre = curr
curr = 1
count = min(pre, curr)
return count
Reference
- https://leetcode.com/problems/count-binary-substrings/