Problem Description After the 32nd ACM/ICPC regional contest, Wiskey is beginning to prepare for CET-6. He has an English words table and read it every morning. One day, Wiskey’s chum wants to play a joke on him. He rolling the table, and tell Wiskey how many time he rotated. Rotate 90 degrees clockwise or count-clockwise each time. The table has n*n grids. Your task is tell Wiskey the final status of the table.
Input Each line will contain two number. The first is postive integer n (0 < n <= 10). The seconed is signed 32-bit integer m. if m is postive, it represent rotate clockwise m times, else it represent rotate count-clockwise -m times. Following n lines. Every line contain n characters.
Output Output the n*n grids of the final status.
Sample Input 3 2 123 456 789 3 -1 123 456 789
Sample Output 987 654 321 369 258 147
(注意是字符啊！字符！我开始以为是n*n个1-n*n的数字。。。WA了几次) 输入n*n个字符，每次旋转以90°为单位，m>0表示顺时针旋转 m<0逆时针旋转。 矩阵旋转后存在四种状态。所以将m取余4，然后判断是哪种状态，然后旋转即可。
代码语言：javascript复制import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while(sc.hasNext()){
int n = sc.nextInt();
int m = sc.nextInt();
String strs[]=new String[n];
for(int i=0;i<n;i ){
strs[i]=sc.next();
}
if(m%4==0){
for(int i=0;i<n;i ){
System.out.println(strs[i]);
}
continue;
}
if(m>0){
m=m%4;
if(m==1){
for(int i=0;i<n;i ){
for(int j=n-1;j>=0;j--){
System.out.print(strs[j].charAt(i));
}
System.out.println();
}
continue;
}
if(m==2){
for(int i=n-1;i>=0;i--){
for(int j=n-1;j>=0;j--){
System.out.print(strs[i].charAt(j));
}
System.out.println();
}
continue;
}
if(m==3){
for(int i=n-1;i>=0;i--){
for(int j=0;j<n;j ){
System.out.print(strs[j].charAt(i));
}
System.out.println();
}
continue;
}
}
if(m<0){
m=m*(-1);
m=m%4;
if(m==3){
for(int i=0;i<n;i ){
for(int j=n-1;j>=0;j--){
System.out.print(strs[j].charAt(i));
}
System.out.println();
}
continue;
}
if(m==2){
for(int i=n-1;i>=0;i--){
for(int j=n-1;j>=0;j--){
System.out.print(strs[i].charAt(j));
}
System.out.println();
}
continue;
}
if(m==1){
for(int i=n-1;i>=0;i--){
for(int j=0;j<n;j ){
System.out.print(strs[j].charAt(i));
}
System.out.println();
}
}
}
}
}
}
