【HDU 1228】A + B

2020-05-31 23:38:19 浏览数 (1)

Description

读入两个小于100的正整数A和B,计算A B.  需要注意的是:A和B的每一位数字由对应的英文单词给出. 

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出. 

Output

对每个测试用例输出1行,即A B的值. 

Sample Input

one two = three four five six = zero seven eight nine = zero zero =

Sample Output

3 90 96

代码语言:javascript复制
#include<stdio.h>
#include<string.h>
char str[1024],letter[10][10]= {"zero","one","two",
"three","four","five","six","seven","eight","nine"};
int flag,a,b,num;
int main()
{
    while(~scanf("%s",str))
    {
        if(strcmp(str,"="))//不为=
        {
            for(int i=0; i<10; i  )
                if(!strcmp(letter[i],str))//为数字i
                {
                    num=i;
                    if(!flag) a=a*10 num;// 前,统计i
                    else b=b*10 num;
                    break;
                }
            if(!strcmp(str," ")) flag=!flag;//为 
        }
        else
        {
            if(!a&&!b)break;
            printf("%dn",a b);
            a=b=0;//不要忘记清零
        }
    }
    return 0;
}

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