挑战程序竞赛系列（73）：4.7高度数组（3）
传送门：POJ 3729: Facer’s String
题意：
公共子串： 给出两个字符串A,B,求满足下列条件的C的个数: 1. C是A的子串 2. C也是B的子串 3. C加上其在A中的后继字符(若在最尾则加上空格字符)不能够在B中出现
其实就是问A中有多少个长度为K的子串在B中刚好存在,且再加上后一个字符形成的子串在B中不存在.
思路： 求出A中存在多少后缀，使得其和B的前缀长度大于等于k，再求出A中存在多少后缀，使得其和B的前缀长度等于k 1，最后两式相减。
所以在>=k的范围内，存在一个B，就可以统计A的后缀个数了，若没有B，则统计也没用。
代码如下：
代码语言：javascript复制import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.Comparator;
import java.util.Map;
import java.util.StringTokenizer;
public class Main{
String INPUT = "./data/judge/201709/P3729.txt";
public static void main(String[] args) throws IOException {
new Main().run();
}
class SuffixArray {
int k = 1;
int n;
Integer[] sa;
int[] rank, tmp;
int[] lcp;
SuffixArray(int[] arra) {
n = arra.length;
sa = new Integer[n 1];
rank = new int[n 1];
tmp = new int[n 1];
lcp = new int[n];
for (int i = 0; i <= n; i) {
sa[i] = i;
rank[i] = i < n ? arra[i] : -1;
}
for (k = 1; k <= n; k <<= 1) {
Arrays.sort(sa, cmp);
tmp[sa[0]] = 0;
for (int i = 1; i <= n; i) {
tmp[sa[i]] = tmp[sa[i - 1]] (cmp.compare(sa[i - 1], sa[i]) < 0 ? 1 : 0);
}
for (int i = 0; i <= n; i) {
rank[i] = tmp[i];
}
}
// lcp
int h = 0;
for (int i = 0; i <= n; i)
rank[sa[i]] = i;
for (int i = 0; i < n; i) {
int j = sa[rank[i] - 1];
if (h > 0)
h--;
for (; i h < n && j h < n; h) {
if (arra[i h] != arra[j h])
break;
}
lcp[rank[i] - 1] = h;
}
}
Comparator<Integer> cmp = new Comparator<Integer>() {
@Override
public int compare(Integer o1, Integer o2) {
int i = o1;
int j = o2;
if (rank[i] != rank[j])
return rank[i] - rank[j];
else {
int ri = i k <= n ? rank[i k] : -1;
int rj = j k <= n ? rank[j k] : -1;
return ri - rj;
}
}
};
}
void read() {
while (more()) {
int m = ni();
int n = ni();
int k = ni();
int[] arra = new int[m n 1];
for (int i = 0; i < m; i) {
arra[i] = ni();
arra[i] ;
}
arra[m] = 10000 8;
for (int i = 0; i < n; i) {
arra[i m 1] = ni();
arra[i m 1] ;
}
SuffixArray sa = new SuffixArray(arra);
out.println(solve(k, m, sa) - solve(k 1, m, sa));
}
}
int solve(int k, int m, SuffixArray sa) {
int ans = 0, A = 0, B = 0;
for (int i = 0; i < sa.n; i ) {// 统计lcp[i]>=k的连续区间内的A子串
if (sa.lcp[i] < k) {
if (B > 0)
ans = A;
A = 0;
B = 0;
}
if (sa.sa[i 1] < m)
A ;
else
B ;
}
return ans;
}
FastScanner in;
PrintWriter out;
void run() throws IOException {
boolean oj;
try {
oj = !System.getProperty("user.dir").equals("F:\java_workspace\leetcode");
} catch (Exception e) {
oj = System.getProperty("ONLINE_JUDGE") != null;
}
InputStream is = oj ? System.in : new FileInputStream(new File(INPUT));
in = new FastScanner(is);
out = new PrintWriter(System.out);
long s = System.currentTimeMillis();
read();
out.flush();
if (!oj) {
System.out.println("[" (System.currentTimeMillis() - s) "ms]");
}
}
public boolean more() {
return in.hasNext();
}
public int ni() {
return in.nextInt();
}
public long nl() {
return in.nextLong();
}
public double nd() {
return in.nextDouble();
}
public String ns() {
return in.nextString();
}
public char nc() {
return in.nextChar();
}
class FastScanner {
BufferedReader br;
StringTokenizer st;
boolean hasNext;
public FastScanner(InputStream is) throws IOException {
br = new BufferedReader(new InputStreamReader(is));
hasNext = true;
}
public String nextToken() {
while (st == null || !st.hasMoreTokens()) {
try {
st = new StringTokenizer(br.readLine());
} catch (Exception e) {
hasNext = false;
return "##";
}
}
return st.nextToken();
}
String next = null;
public boolean hasNext() {
next = nextToken();
return hasNext;
}
public int nextInt() {
if (next == null) {
hasNext();
}
String more = next;
next = null;
return Integer.parseInt(more);
}
public long nextLong() {
if (next == null) {
hasNext();
}
String more = next;
next = null;
return Long.parseLong(more);
}
public double nextDouble() {
if (next == null) {
hasNext();
}
String more = next;
next = null;
return Double.parseDouble(more);
}
public String nextString() {
if (next == null) {
hasNext();
}
String more = next;
next = null;
return more;
}
public char nextChar() {
if (next == null) {
hasNext();
}
String more = next;
next = null;
return more.charAt(0);
}
}
static class ArrayUtils {
public static void fill(int[][] f, int value) {
for (int i = 0; i < f.length; i) {
Arrays.fill(f[i], value);
}
}
public static void fill(int[][][] f, int value) {
for (int i = 0; i < f.length; i) {
fill(f[i], value);
}
}
public static void fill(int[][][][] f, int value) {
for (int i = 0; i < f.length; i) {
fill(f[i], value);
}
}
}
}
