代码语言：javascript复制
[root@Singapore numpy]# wget https://pypi.python.org/packages/ee/66/7c2690141c520db08b6a6f852fa768f421b0b50683b7bbcd88ef51f33170/numpy-1.14.0.zip
[root@Singapore numpy]# md5sum numpy-1.14.0.zip
c12d4bf380ac925fcdc8a59ada6c3298 numpy-1.14.0.zip
[root@Singapore numpy]# unzip numpy-1.14.0.zip
[root@Singapore numpy]# cd numpy-1.14.0
[root@Singapore numpy-1.14.0]# cat INSTALL.rst.txt #安装说明
[root@Singapore numpy-1.14.0]# python3 setup.py build install --prefix /root/python/numpy #注意安装路径
[root@Singapore numpy-1.14.0]# echo "export PYTHONPATH=/root/python/numpy/lib/python3.6/site-packages" >> ~/.bashrc #注意安装路径
[root@Singapore numpy-1.14.0]# . ~/.bashrc
[root@Singapore numpy-1.14.0]# echo $?
0
[root@Singapore numpy-1.14.0]# 写一个线性回归 试一试
代码语言：javascript复制[root@Singapore work.dir]# cat SimpleLineRegression.py
#!/usr/bin/python3
import numpy as np
def fitSLR(x,y):
n = len(x)
dinominator = 0
numerator = 0
for i in range(0, n):
numerator = (x[i] - np.mean(x)) * (y[i] - np.mean(y))
dinominator =(x[i] - np.mean(x)) ** 2
print ("numerator:", numerator)
print ("dinominator", dinominator)
b1 = numerator/float(dinominator)
b0 = np.mean(y)/float(np.mean(x))
return b0, b1
def predict(x, b0, b1):
return b0 x*b1
x = [1,3,2,1,3]
y = [14,24,18,17,27]
b0, b1 = fitSLR(x,y)
print ("intercept:", b0, " slope:", b1)
x_test = 6
y_test = predict(6, b0, b1)
print("y_test", y_test)
[root@Singapore work.dir]# ./SimpleLineRegression.py
numerator: 20.0
dinominator 4.0
intercept: 10.0 slope: 5.0
y_test 40.0
[root@Singapore work.dir]# 
