Python条件语句与循环

2020-01-06 20:02:15 浏览数 (2)

1、判断与循环 python 缩进 main: print("Hello") print("Hello world.")

代码语言:javascript复制
if 判断条件:
    执行语句
elif 判断条件:
    执行语句
else:
    执行语句
代码语言:javascript复制
while 判断条件:
    执行语句
代码语言:javascript复制
a = 100
while a>1:
    print(a)
    a-=1
    if a==50:
        break   # 退出循环
    if a==55:
        print("5555555555")
        continue   # 此次循环结束,进入下一个循环

break 跳出循环 continue 进入下一次循环

代码语言:javascript复制
for item in sequence:
   执行语句
代码语言:javascript复制
l = ["a","b","c","d","e","f"]
print(l[:])
print(l[0:5])        # 大于等于0     小于5  0 <= a > 5
print(l[0:-1])        # 大于等于0     小于5  0 <= a > 5
for x,y in enumerate(l):    # 打印列表中元素以及下标
    print(x,y)

2、编程思想最重要

编程语言最重要的是思想 ABCD乘以9=DCBA,求A=?,B=?,C=?,D=?

代码语言:javascript复制
for A in range(1,10):
    for B in range(0,10):
        for C in range(0,10):
            for D in range(1,10):
                start = 1000*A 100*B 10*C D
                end = 1000*D 100*C 10*B A
                if start * 9 == end:
                    print("A={}".format(A))
                    print("B={}".format(B))
                    print("C={}".format(C))
                    print("D={}".format(D))
                    print("{0} * 9 = {1}".format(start,end))

返回结果: A=1 B=0 C=8 D=9 1089 * 9 = 9801

3、求阶乘 求1-n的阶乘的和 1! 2! 3! 4! 5 ! ··· n! 0! = 1 1!= 1 2!= 1 2 = 2 3!= 1 2 * 3 = 6

代码语言:javascript复制
def one(n):
    total = 1
    if n ==0:
        total = 1
    else:
        for i in range(1,n 1):
            total *= i
    return total
print(one(3))

status=1
while status:
    result = 0
    n= input("Please input a number(n>=0) : ")
    for i in n:
        if not i.isdigit():
            print("The number of you input is error.")
            exit(1)
    if int(n) < 0:
        print("The number of you input is error.")
        break
    for i in range(0,int(n) 1):
        result  = one(i)
    print("0!   1!   2!   ··· ···   n! = {}".format(result))

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