- Permutations
Given a collection of distinct numbers, return all possible permutations.
For example, [1,2,3] have the following permutations: [ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ]
给一堆不同的数,然后让你写成这样上面的样子,就是排列组合。 举个简单例子【1,2,3】吧 刚拿到这3个数 假设开始我们什么都没有,从一个空[]开始, 那现在第一步,我们有三条路:[1],[2],[3] 然后 对[1]来说,有两条路[1,2] ||[1,3],然后这两条路分别只有一条路[1,2,3] ||[1,3,2] 以此类推
代码如下:用递归
代码语言:javascript复制class Solution(object):
def permute(self, nums):
"""
:type nums: List[int]
:rtype: List[List[int]]
"""
self.res = []
sub = []
self.dfs(nums,sub)
return self.res
def dfs(self, Nums, subList):
if len(subList) == len(Nums):
#print res,subList
self.res.append(subList[:])
for m in Nums:
if m in subList:
continue
subList.append(m)
self.dfs(Nums,subList)
subList.remove(m)