Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Example 1:
代码语言:javascript复制Input: [1,3,5,6], 5
Output: 2
Example 2:
代码语言:javascript复制Input: [1,3,5,6], 2
Output: 1
Example 3:
代码语言:javascript复制Input: [1,3,5,6], 7
Output: 4
Example 1:
代码语言:javascript复制Input: [1,3,5,6], 0
Output: 0
代码语言:javascript复制class Solution {
public int searchInsert(int[] nums, int target) {
if(target<nums[0]){
return 0;
}
if(target>nums[nums.length-1]){
return nums.length;
}
for(int i = 0;i<nums.length;i ){
if(target == nums[i]){
return i;
}
if(i 1<nums.length && nums[i]<target && nums[i 1]>target){
return i 1;
}
}
return 0;
}
}