高并发编程系列(一)

2019-10-15 15:42:05 浏览数 (1)

高并发编程系列(一)

High concurrency programming series

对某个对象加锁

代码语言:javascript复制
public class Ta {


    /**
     * synchronized keyword 
     * Locks an object
     */


    private int count = 10;


    private Object o = new Object();


    public void m(){
        synchronized(o){
            count--;
            System.out.println(Thread.currentThread().getName()   "count:"   count);
        }
    }


}

等同于在方法的代码执行时要synchronized

代码语言:javascript复制
public class Tb {

    /**
     * Is equivalent to synchronized when the method's code executes.
     */


    private int count = 10;


    private Object o = new Object();


    public synchronized void m() {
            count--;
            System.out.println(Thread.currentThread().getName()   "count:"   count);
    }


}

任何线程执行下面代码,必须要拿到this 的锁,

记住锁定的时对象 不是代码块 表面看着是代码块

代码语言:javascript复制
public class Tc {


    /**
     * Any thread that executes the following code must get the lock for this,
     * Remember that the object that is locked is not a block of code and it looks like a block of code
     */


    private int count = 10;


    public void m() {
        synchronized(this) {
            count--;
            System.out.println(Thread.currentThread().getName()   "count:"   count);
        }
    }


}

放在静态方法上面,由于静态没有this可以锁定,不需要new 出对象,运用了反射.

代码语言:javascript复制
public class Td {


    /**
     * On the static method, because static no this can be locked, do not need to new out of the object, the use of reflection.
     */


    private static int count = 10;


    private Object o = new Object();


    public synchronized static void m() {
            count--;
            System.out.println(Thread.currentThread().getName()   "count:"   count);
    }


    public void mm() {
        synchronized(Td.class) {  //考虑一下这里写 synchronized (this)  是否可以  不可以
            count--;
            System.out.println(Thread.currentThread().getName()   "count:"   count);
        }
    }


}
代码语言:javascript复制
public class Te implements Runnable {

    private int count = 10;

    @Override
    public synchronized void run() {
        count --;
        System.out.println(Thread.currentThread().getName()   "count:"   count);
    }

    public static void main(String[] args) {

        Te t = new Te();
        for (int i = 0; i<5;i  ){
            new Thread(t,"THREAD"   i).start();
        }

    }
    
}

m1不影响m2,同步方法不影响其他方法,m2 不需要锁.

代码语言:javascript复制
public class Tf {


    /**
     *
     * M1 does not affect m2, synchronous methods do not affect other methods, and m2 does not need a lock.
     */


    public synchronized void m1() {
        System.out.println(Thread.currentThread().getName()   "m1.start....");
        try {
            Thread.sleep(10000);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println(Thread.currentThread().getName()   "m1.end");
    }


    public void m2() {
        try {
            Thread.sleep(5000);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println(Thread.currentThread().getName()   "m2");
    }


    public static void main(String[] args) {
        Tf t = new Tf();


        new Thread(()->t.m1()).start();
        new Thread(()->t.m2()).start();


        /*new Thread(t::m1,"t1").start();
        new Thread(t::m2,"t2").start();*/


       /* new Thread(new Runnable() {
            @Override
            public void run() {
                t.m1();
            }
        });*/


    }


}

对业务写方法加锁.

对业务读方法不加锁.

容易产生脏读问题(dirtyRead).

代码语言:javascript复制
public class Tg {


    /**
     *
     * Locks the business write method.
     * Business read methods are not locked.
     * DirtyRead is easy to produce.
     * No two seconds sleep, no problem, plus there's a dirty read on the read,
     * there's a block of code between two seconds that might be executed by some other program that's not locked.
     * Lock or no lock depends on the business.
     * Tg For the account class  It has a name and a balance
     *
     */


    String name;
    double balance;


    public synchronized void set(String name, double balance) {
        this.name = name;
        try {
            Thread.sleep(2000);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }


        this.balance = balance;
    }


    public /*synchronized*/ double getBalance(String name) {
        return this.balance;
    }


    public static void main(String[] args) {
        Tg t = new Tg();
        new Thread(()->t.set("掌上编程",100.0)).start();


        try{
            TimeUnit.SECONDS.sleep(1);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }


        System.out.println(t.getBalance("掌上编程"));


        try {
            TimeUnit.SECONDS.sleep(2);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println(t.getBalance("掌上编程"));


    }


}

一个同步方法可以调用另外一个同步方法,一个线程已经拥有某个对象,再次申请的时候仍然会得到该对象的锁,

也就是说synchronized 获得锁是可重入的。

代码语言:javascript复制
public class Th {


    /**
     *
     * One synchronized method can call another, and a thread that already owns an object will still get its lock when it requests it again.
     * That is, synchronized acquired locks are reentrant.
     */


    synchronized void m1() {
        System.out.println("m1.start");
        try {
            TimeUnit.SECONDS.sleep(1);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        m2();
    }


    synchronized void m2() {
        try {
            TimeUnit.SECONDS.sleep(2);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println("m2");
    }


}

一个同步的方法可以调用另外一个同步方法.一个线程已经拥有某个对象的锁,再次申请的时候仍然会得到该对象的锁.也就是说 synchronized获得的锁是可重入的.这里是继承中有可能发生的情形,子类调用父类的同步方法.

代码语言:javascript复制
public class Ti {
    synchronized void m() {
    
        System.out.println("m.start");
        try{
            TimeUnit.SECONDS.sleep(1);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println("m.end");
    }


    public static void main(String[] args) {
        new TiTi().m();
    }


}


class TiTi extends Ti {


    @Override
    synchronized void m(){
        System.out.println("child m start");
        super.m();
        System.out.println("child m end");
    }


}

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