Leetcode 145 Binary Tree Postorder Traversal

Given a binary tree, return the postorder traversal of its nodes' values.

For example: Given binary tree {1,#,2,3},

代码语言：javascript复制

   1
    
     2
    /
   3

return [3,2,1].

二叉树后序遍历，easy

代码语言：javascript复制

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    void dfs(TreeNode* root, vector<int> &res)  
    {  
        if(root->left) dfs(root->left, res);  
        if(root->right) dfs(root->right, res); 
        res.push_back(root->val); 
    }  
    vector<int> postorderTraversal(TreeNode* root) {
        vector<int> res;  
        if(root) dfs(root, res);  
        return res;
    }
};

binary nodes return traversal tree

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