Follow up for "Remove Duplicates": What if duplicates are allowed at most twice?
For example,
Given sorted array nums = [1,1,1,2,2,3]
,
Your function should return length = 5
, with the first five elements of nums being 1
, 1
, 2
, 2
and 3
. It doesn't matter what you leave beyond the new length.
删除重复第三次及以上的数字,并返回删除后的长度。
两个指针解决,快指针扫描,慢指针保存保留的数字。
代码语言:javascript复制class Solution {
public:
int removeDuplicates(vector<int>& nums)
{
int result=nums.size(),pre=1;
for(int i=1,j=1;i<nums.size();i )
{
if(nums[i]==nums[i-1])
{
pre ;
if(pre>2)
result--;
else
nums[j ]=nums[i];
}
else
{
pre=1;
nums[j ]=nums[i];
}
}
return result;
}
};