Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.
For example, Given the following matrix:
代码语言:javascript复制[
[ 1, 2, 3 ],
[ 4, 5, 6 ],
[ 7, 8, 9 ]
]
You should return [1,2,3,6,9,8,7,4,5]
.
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旋转取数,模拟,注意边界情况
代码语言:javascript复制class Solution {
public:
vector<int> spiralOrder(vector<vector<int>>& matrix) {
vector<int> result;
int m=matrix.size();
if(m==0) return result;
int n=matrix[0].size(),x=0,y=0;
for(;x<m && y<n;x ,y ,m--,n--)
{
for(int i=y;i<n;i ) result.push_back(matrix[x][i]);
for(int i=x 1;i<m;i ) result.push_back(matrix[i][n-1]);
for(int i=n-2;i>=y && x!=m-1;i--) result.push_back(matrix[m-1][i]);//x==m-1时此行已填
for(int i=m-2;i>x && y!=n-1;i--) result.push_back(matrix[i][y]);//i>x,因为首行第一个元素开始已填
}
return result;
}
};