Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
和62,63如出一辙的套路,没什么含量
代码语言:javascript复制class Solution {
public:
int minPathSum(vector<vector<int>>& grid) {
if(grid.size()==0) return 0;
for(int i=1;i<grid.size();i )
grid[i][0] =grid[i-1][0];
for(int i=1;i<grid[0].size();i )
grid[0][i] =grid[0][i-1];
for(int i=1;i<grid.size();i )
for(int j=1;j<grid[0].size();j )
grid[i][j] =min(grid[i-1][j],grid[i][j-1]);
return grid[grid.size()-1][grid[0].size()-1];
}
};