版权声明:原创勿转 https://cloud.tencent.com/developer/article/1412858
思路
考虑到负负得正的情况,需要同时记录最大值和最小值
code
代码语言:javascript复制func maxProduct(nums []int) int {
prevMax, prevMin, ret := nums[0], nums[0], nums[0]
for i := 1; i < len(nums); i {
if nums[i-1] == 0 {
prevMax, prevMin = nums[i], nums[i]
} else {
curMax := max(nums[i], max(nums[i]*prevMax, nums[i]*prevMin))
curMin := min(nums[i], min(nums[i]*prevMax, nums[i]*prevMin))
prevMax, prevMin = curMax, curMin
}
ret = max(prevMax, ret)
}
return ret
}
func max(x, y int) int {
if x > y {
return x
}
return y
}
func min(x, y int) int {
if x > y {
return y
}
return x
}