前面已经实现了雷区的扫描，现在就是要根据已知情况计算哪个方块底下是雷、哪个方块底下是空白，在初级、中级难度下只要计算每个方块周围的8个方块就好。
code
如果周围8个方块和当中数字判断周围有雷
% 插旗
function banner()
global map
global blocks_x
global blocks_y
global left
global top
global block_width
global block_height
showmap()
for y=1:blocks_y
for x=1:blocks_x
if (1 <= map(x,y)) && (map(x,y) <= 8)
boom_number = map(x,y);
block_white = 0;
block_qi = 0;
for yy=(y - 1):(y 1)
for xx=(x - 1):(x 1)
if (1 <= yy) && (1 <= xx) && (yy <= blocks_y) && (xx <= blocks_x)
if ~((yy == y) && (xx == x))
if map(xx,yy) == 0
block_white = block_white 1;
elseif map(xx,yy) == -4
block_qi = block_qi 1;
end
end
end
end
end
if boom_number == block_white block_qi
for yy=(y - 1):(y 1)
for xx=(x - 1):(x 1)
if (1 <= yy) && (1 <= xx) && (yy <= blocks_y) && (xx <= blocks_x)
if ~((yy == y) && (xx == x))
if map(xx,yy) == 0
disp("插旗")
win.setMouse(left (xx-1) * block_width 5,...
top (yy-1) * block_height 5);
win.rightClick;
showmap();
end
end
end
end
end
end
end
end
end
end
code
如果周围8个方块和当中数字判断周围有空白方块
% 点击白块
function click_blank()
global map
global blocks_x
global blocks_y
global left
global top
global block_width
global block_height
showmap();
iscluck = 0;
for y=1:blocks_y
for x=1:blocks_x
if (1 <= map(x,y)) && (map(x,y) <= 8)
boom_number = map(x,y);
block_white = 0;
block_qi = 0;
for yy=(y - 1):(y 1)
for xx=(x - 1):(x 1)
if (1 <= yy) && (1 <= xx) && (yy <= blocks_y) && (xx <= blocks_x)
if ~((yy == y) && (xx == x))
if map(xx,yy) == 0
block_white = block_white 1;
elseif map(xx,yy) == -4
block_qi = block_qi 1;
end
end
end
end
end
if boom_number == block_qi && block_white > 0
for yy=(y - 1):(y 1)
for xx=(x - 1):(x 1)
if (1 <= yy) && (1 <= xx) && (yy <= blocks_y) && (xx <= blocks_x)
if ~((yy == y) && (xx == x))
if map(xx,yy) == 0
disp("点开")
win.setMouse(left (xx-1) * block_width 5,...
top (yy-1) * block_height 5);
win.leftClick;
iscluck = 1;
end
end
end
end
end
end
end
end
end
if iscluck == 0 && ~all(all(map~=0))
luck();
end
win.setMouse(50,50);
end
