1. Description
2. Solution
代码语言:javascript
复制/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
bool hasCycle(ListNode *head) {
if(!head || !head->next) {
return false;
}
ListNode* slow = head;
ListNode* fast = head->next;
if(slow == fast) {
return true;
}
while(slow != fast) {
if(fast == nullptr || fast->next == nullptr) {
return false;
}
slow = slow->next;
fast = fast->next->next;
}
return true;
}
};