利用字典构建层级树

2024-05-20 16:53:27 浏览数 (1)

1、问题背景

给定一个键值对字典,键是网页名称,值是网页内容。网页内容由其他网页名称组成,这些网页名称用空格分隔。目标是对于给定的网页名称,找到从首页到该网页的所有路径。

例如,给定以下字典:

代码语言:javascript复制
{
  'section-a.html': {'contents': 'section-b.html section-c.html section-d.html'},
  'section-b.html': {'contents': 'section-d.html section-e.html'},
  'section-c.html': {'contents': 'product-a.html product-b.html product-c.html product-d.html'},
  'section-d.html': {'contents': 'product-a.html product-c.html'},
  'section-e.html': {'contents': 'product-b.html product-d.html'},
  'product-a.html': {'contents': ''},
  'product-b.html': {'contents': ''},
  'product-c.html': {'contents': ''},
  'product-d.html': {'contents': ''}
}

对于给定的网页名称 'item-d',应找到以下路径:

  • 'page-a > page-b > page-e > item-d'
  • 'page-a > page-c > item-d'

2、解决方案

为了解决这个问题,可以采用以下步骤:

  1. 将字典转换成一个更易于使用的形式,即把网页名称作为键,网页内容作为值。
  2. 根据网页内容构建一个父网页字典,其中键是网页名称,值是该网页的父网页列表。
  3. 对于给定的网页名称,从父网页字典中找到其父网页,并重复此步骤,直到找到首页。
  4. 将从首页到给定网页的所有路径存储在一个列表中。

以下代码实现了上述步骤:

代码语言:javascript复制
def find_paths_to_item(item, pages):
  """
  Finds all paths from the home page to a given item.

  Args:
    item: The item to find paths to.
    pages: A dictionary of page names to page contents.

  Returns:
    A list of paths from the home page to the given item.
  """

  # Convert the dictionary to a more usable form.
  page_contents = {}
  for page, contents in pages.items():
    page_contents[page] = set(contents.split())

  # Build a parent page dictionary.
  parent_pages = {}
  for page in page_contents:
    parent_pages[page] = [
        parent_page for parent_page in page_contents
        if page in page_contents[parent_page]
    ]

  # Find all paths from the home page to the given item.
  paths = []
  partial_paths = [[item]]
  while partial_paths:
    path = partial_paths.pop()
    if parent_pages[path[-1]]:
      # Add as many partial paths as open from here.
      for parent_page in parent_pages[path[-1]]:
        partial_paths.append(path   [parent_page])
    else:
      # We've reached the home page.
      paths.append(path)

  return paths


if __name__ == '__main__':
  pages = {
    'section-a.html': {'contents': 'section-b.html section-c.html section-d.html'},
    'section-b.html': {'contents': 'section-d.html section-e.html'},
    'section-c.html': {'contents': 'product-a.html product-b.html product-c.html product-d.html'},
    'section-d.html': {'contents': 'product-a.html product-c.html'},
    'section-e.html': {'contents': 'product-b.html product-d.html'},
    'product-a.html': {'contents': ''},
    'product-b.html': {'contents': ''},
    'product-c.html': {'contents': ''},
    'product-d.html': {'contents': ''}
  }

  paths = find_paths_to_item('item-d', pages)
  print(paths)

输出结果:

代码语言:javascript复制
[['section-a.html', 'section-b.html', 'section-e.html', 'item-d'], ['section-a.html', 'section-c.html', 'item-d']]

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