【海贼王编程冒险 - C语言海上篇】怎样用C语言实现简单的扫雷游戏？

1 -> test.c

代码语言：javascript复制

#define _CRT_SECURE_NO_WARNINGS 1

#include "game.h"

void menu()
{
	printf("************************************n");
	printf("*********       1.play      ********n");
	printf("*********       0.exit      ********n");
	printf("************************************n");
}

void game()
{
	//show数组为排查出的雷的信息
	char show[ROWS][COLS] = { 0 };
	//mine数组为布置好的雷的信息
	char mine[ROWS][COLS] = { 0 };

	//初始化棋盘
	InitBoard(show, ROWS, COLS, '*');
	InitBoard(mine, ROWS, COLS, '0');

	//打印棋盘
	DisplayBoard(show, ROW, COL);

	//布置雷
	SetMine(mine, ROW, COL);
	//DisplayBoard(mine, ROW, COL);

	//排查雷
	FineMine(mine, show, ROW, COL);
}

int main()
{
	int input = 0;
	srand((unsigned int)time(NULL));
	do
	{
		menu();
		printf("请选择:>");
		scanf("%d", &input);
		switch (input)
		{
		case 1:
			game();
			break;
		case 0:
			printf("退出游戏n");
			break;
		default:
			printf("输入错误，请重新输入。n");
			break;
		}

	} while (input);

	return 0;
}

2 -> game.c

代码语言：javascript复制

#define _CRT_SECURE_NO_WARNINGS 1

#include "game.h"

//初始化棋盘
void InitBoard(char board[ROWS][ROWS], int rows, int cols, char set)
{
	memset(&board[0][0], set, rows * cols * sizeof(board[0][0]));
}

//打印棋盘
void DisplayBoard(char board[ROWS][ROWS], int row, int col)
{
	printf("******  扫雷  ******n");
	for (int j = 0; j <= col; j  )
	{
		printf("%d ", j);
	}
	printf("n");
	for (int i = 1; i <= row; i  )
	{
		printf("%d ", i);
		for (int j = 1; j <= col; j  )
		{
			printf("%c ", board[i][j]);
		}
		printf("n");
	}
}

//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col)
{
	int cnt = EASY_COUNT;

	while (cnt)
	{
		int x = rand() % row   1;
		int y = rand() % col   1;
		if (mine[x][y] == '0')
		{
			mine[x][y] = '1';
			cnt--;
		}
	}
}

//计算周围雷的数量
int GetMineCount(char mine[ROWS][COLS], int x, int y)
{
	return (mine[x - 1][y - 1]  
		mine[x - 1][y]  
		mine[x - 1][y   1]  
		mine[x][y - 1]  
		mine[x][y   1]  
		mine[x   1][y - 1]  
		mine[x   1][y]  
		mine[x   1][y   1] - 8 * '0');
}

//排查雷
void FineMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
	int x = 0;
	int y = 0;
	int win = 0;
	while (win < row * col - EASY_COUNT)
	{
		printf("请输入坐标:>");
		scanf("%d %d", &x, &y);
		if (x >= 1 && x <= row && y >= 1 && y <= col)
		{
			if (mine[x][y] == '1')
			{
				printf("很遗憾，排雷失败。n");
				DisplayBoard(mine, ROW, COL);
				break;
			}
			else
			{
				int cnt = GetMineCount(mine, x, y);
				show[x][y] = cnt   '0';
				DisplayBoard(show, ROW, COL);
				win  ;
			}
		}
		else
		{
			printf("坐标输入错误，请重新输入n");
		}
	}
	if (win == row * col - EASY_COUNT)
	{
		printf("恭喜你排雷成功!!!n");
	}
}

3 -> game.h

代码语言：javascript复制

#pragma once

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

//棋盘大小
#define ROW 9
#define COL 9
#define ROWS ROW   2
#define COLS COL   2
//雷的个数
#define EASY_COUNT 10

//初始化棋盘
void InitBoard(char board[ROWS][ROWS], int rows, int cols, char set);

//打印棋盘
void DisplayBoard(char board[ROWS][ROWS], int row, int col);

//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col);

//计算周围雷的数量
int GetMineCount(char mine[ROWS][COLS], int x, int y);

//排查雷
void FineMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

代码里的注释感觉已经很清楚啦，就不多讲解啦

感谢各位大佬的支持！！！

游戏 int rows 编程 数组

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