代码语言：javascript复制
# 引入re，贯穿所有练习题
import re1.1 下面这段话中出现频率最高的单词是什么
代码语言：javascript复制paragraph = 'I love teaching. If you do not love teaching what else can you love. I love Python if you do not love something which can give you all the capabilities to develop an application what else can you love.'
words = re.findall(r'w ', paragraph) # 通过正则提取所有单词
word_dict = dict() # 通过字典统计
for word in words:
if word in word_dict:
word_dict[word] = 1
else:
word_dict[word] = 1
word_tuple = [(v, k) for k,v in word_dict.items()] #转元组list
word_sort = sorted(word_tuple, reverse=True) # 内置排序
print(word_sort)
1.2 提取对话中x轴点数字并计算最远点距离
代码语言：javascript复制conents = "The position of some particles on the horizontal x-axis are -12, -4, -3 and -1 in the negative direction, 0 at origin, 4 and 8 in the positive direction."
points = re.findall("[-]*d ", conents)
print("points=", points)
change_to_int = [int(i) for i in points]
sorted_points = sorted(change_to_int)
print("sorted_points=", sorted_points)
distance = abs(sorted_points[0]) abs(sorted_points[-1])
print("distance=", distance)
2.1 编写一个方法来识别字符串是否是有效的python变量
关于合法python变量名的定义如果忘记请回看day2内容
代码语言：javascript复制def is_valid_variable(name):
if re.match(r"^[^0-9][a-zA-Z0-9_] $", name) is None:
return False
else:
return True
print("Name 字符是否符合变量命名规则：", is_valid_variable("Name"))
print("_Test字符是否符合变量命名规则：", is_valid_variable("_Test"))
print("Number8899 字符是否符合变量命名规则：", is_valid_variable("Number8899"))
print("char$% 字符是否符合变量命名规则：", is_valid_variable("char$3"))
print("98abc 字符是否符合变量命名规则：", is_valid_variable("98abc"))
3.1 清除以下文本无用的字符。且统计出优化后的文本中出现频率最高的三个单词。
代码语言：javascript复制sentence = '''%I $am@% a %tea@cher%, &and& I lo%#ve %tea@ching%;. There $is nothing; &as& mo@re rewarding as educa@ting &and& @emp%o@wering peo@ple. ;I found tea@ching m%o@re interesting tha@n any other %jo@bs. %Do@es thi%s mo@tivate yo@u to be a tea@cher!?'''
def clean_text(sentence):
split_blank = re.findall("[^ ] ", sentence)
word_list = []
for chars in split_blank:
word = re.sub("W ", '', chars)
word_list.append(word)
return " ".join(word_list)
def most_frequent_words(clean_text):
# 统计处理方法参考练习1.1，需要注意的此函数最终只需要返回排序后前三个单词
# 这里给出围绕本章节知识点另外一种解法供参考，当然方法肯定还有很多，
# 尝试你的思路(不限制正则)，看看能不能有更多更好的办法呢？
split_word = re.findall("w ", cleaned_text)
unique_word = list(set(split_word))
top_one = top_two = top_three = ('', 0)
for uword in unique_word:
find_word = re.findall(uword, clean_text)
word_count = len(find_word)
if word_count > top_one[1]:
top_three = top_two
top_two = top_one
top_one = (uword, word_count)
elif word_count > top_two[1]:
top_three = top_two
top_two = (uword, word_count)
elif word_count > top_three[1]:
top_three = (uword, word_count)
else:
pass
return [top_one, top_two, top_three]
cleaned_text = clean_text(sentence)
print(cleaned_text)
print(most_frequent_words(cleaned_text)) # 因题目中可能存在多个相同排第三的所以结果每次运行结果会变
